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2 years ago

Plzzzzz Answer this its some easy points, I'm legit just dumb. Answer both questions.

Mathematics

2 answers:

Liono4ka [1.6K]2 years ago

7 0

Answer:

A) Each of the smaller donations is $20.

B) The larger donation is greater than the smaller donations by $15.

Step-by-step explanation:

4+4+7 is equal to 15, and divide 75 by 15 to get $5 per part. Multiply 4 by 5 to get $20 for a smaller donation, and 7 by 5 to get $35 for the larger donation. Hope this helped :)

svetlana [45]2 years ago

3 0

Answer:

Smaller donations each cost $20

The bigger donation is $15 more than the smaller ones.

Step-by-step explanation:

Let 4x be defined as the amount of the smaller donation, and let 7x be defined as the larger amount of the donation. We can then set up an equation:

4x+4x+7x = 75

15x = 75

x = 5

We can now plugin 5 for x to solve for the smaller donation and the larger donation:

Smaller donation = 4*5 = 20

Bigger donation = 7*5 = 35

Now, to find how much greater the bigger donation is, we just subtract 35 from 20, which is 15.

I hope this helped.

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Tasya [4]

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3 years ago

the temperature of an oven went through 330 degrees to 390 degrees what is the percentage increase in temperature

valentina_108 [34]

All you do is divide.
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3 years ago

3x+y=14<br> Rewrite equation in slope-intercept form(solve y)

attashe74 [19]

Y = -3x + 14
Subtracted 3x from both sides

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2 years ago

Read 2 more answers

Help me with question a please ! With full workings !

frosja888 [35]

A)

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
P&({{ 0.5}}\quad ,&{{ 0}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}$

$\bf QP=\sqrt{(0.5-0)^2+(0-2)^2}\implies QP=\sqrt{0.5^2+2^2}
\\\\\\
QP=\sqrt{\left( \frac{1}{2} \right)^2+4}\implies QP=\sqrt{ \frac{1^2}{2^2}+4}\implies QP=\sqrt{\frac{1}{4}+4}
\\\\\\
QP=\sqrt{\frac{17}{4}}\implies QP=\cfrac{\sqrt{17}}{\sqrt{4}}\implies QP=\cfrac{\sqrt{17}}{2}$

b)

since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP

thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)

c)

what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
R&({{ -0.5}}\quad ,&{{ 0}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-2}{-0.5-0}\implies \cfrac{-2}{-0.5}$

$\bf m=\cfrac{\frac{-2}{1}}{-\frac{1}{2}}\implies \cfrac{-2}{1}\cdot \cfrac{2}{-1}\implies 4
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=4(x-0)\implies y=4x+2\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}$

7 0

2 years ago

James is playing his favorite game at the arcade. After playing the game 333 times, he has 888 tokens remaining. He initially ha

lesantik [10]

Answer:

t(g)= -4g + 20

Step-by-step explanation:

James is playing his favorite game at the arcade. After playing the game 3 times, he has 8 tokens remaining. He initially had 20 tokens, and the game costs the same number of tokens each time. The number tt of tokens James has is a function of gg, the number of games he plays

Solution

Let

g=No. of games James plays

t= No. of tokens James has.

Find the slope using

y=mx + b

Where,

m = Slope of line,

b = y-intercept.

Before James started playing the games, he has a total of 20 tokens.

That is, when g=0, t=20

After James played the games 3 times, he has 8 tokens left

That is, when g=3, t=8

(x,y)

(0,20) (3,8)

m=y2-y1 / x2-x1

=(8-20) / (3-0)

= -12 / 3

m= -4

Slope of the line, m= -4

y=mx + b

No. of tokens left depend on No. of games James plays

t is a function of g.

t(g)

t(g)= -4g + 20

3 0

2 years ago