Answer:
well idk but i will take the points
Explanation:
Answer:
-179.06 kJ
Explanation:
Let's consider the following balanced reaction.
HCl(g) + NaOH(s) ⟶ NaCl(s) + H₂O(l)
We can calculate the standard enthalpy change for the reaction (ΔH°r) using the following expression.
ΔH°r = 1 mol × ΔH°f(NaCl(s)) + 1 mol × ΔH°f(H₂O(l)) - 1 mol × ΔH°f(HCl(g)) - 1 mol × ΔH°f(NaOH(s))
ΔH°r = 1 mol × (-411.15 kJ/mol) + 1 mol × (-285.83 kJ/mol) - 1 mol × (-92.31 kJ/mol) - 1 mol × (-425.61 kJ/mol)
ΔH°r = -179.06 kJ
Answer:
Isotopes are atoms of the same element with the same number of protons but different number of neutrons.
Hope this helps.
The answer for the following problem is explained below.
- <u><em>Therefore 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.</em></u>
Explanation:
Given:
mass of methane = 6.00 × 10^-3 grams
+
→
+
Firstly balance the following equation:
Before balancing the equation:
→ 
After balancing the equation:
→ 
where;
represents methane molecule
represents oxygen molecule
represents carbon dioxide molecule
represents water molecule
+2
→
+ 2
16 grams of methane → 44 grams of carbon dioxide
6 × 10^-3 grams of methane → ?
= 
= 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.
<u><em>Therefore 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.</em></u>
Answer: 336.2K
Explanation:
The boiling point is obtained from the standard enthalpy and entropy of vaporization as shown in the image attached.
Standard enthalpy of vaporization=35.3KJmol-1=35.3×10^3 Jmol-1
Standard entropy of vaporization= 105 JMol-1K-1
The formula and details of the solution are shown in the image attached.