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Jlenok [28]
3 years ago
13

Avogadro constant is 6.02 1023 (the number of atoms or molecules per mole). What how much charge is there in 1 mole of electrons

? How much charge is there in 1 mole of hydrogen ions (H+). Remember that hydrogen consists of one electron and one proton, so hydrogen ions are just protons.
Chemistry
1 answer:
cupoosta [38]3 years ago
8 0

Answer:

Charge of 1 mole of electrons = -96488.46 C

Charge of 1 mole of protons/ hydrogen ions = +96488.46 C

Explanation:

Given, Avogadro constant:-

N_a=6.023\times 10^{23}

Thus, charge on 1 mole of electron can be calculated as:-

Charge on 1 electron = -1.602\times 10^{-19}\ C

Charge on 6.023\times 10^{23} electrons = -1.602\times 10^{-19}\times 6.023\times 10^{23}\ C = -96488.46 C

Charge of 1 mole of electrons = -96488.46 C

Charge of electron = Charge on proton (magnitude), Only the charge is different. Electron has negative charge and protons have positive charge.

Charge of 1 mole of protons/ hydrogen ions = +96488.46 C

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How many atoms of oxygen are present in 7.51 grams of<br> glycine with formula C₂H5O2N?
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1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N. Details about number of atoms can be found below.

How to calculate number of atoms?

The number of atoms of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.

However, the number of moles of oxygen in glycine can be calculated using the following expression:

Molar mass of C₂H5O2N = 75.07g/mol

Mass of oxygen in glycine = 32g/mol

Hence; 32/75.07 × 7.51 = 3.2grams of oxygen in glycine

Moles of oxygen = 3.2g ÷ 16g/mol = 0.2moles

Number of atoms of oxygen = 0.2 × 6.02 × 10²³ = 1.205 × 10²³ atoms

Therefore, 1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N.

Learn more about number of atoms at: brainly.com/question/8834373

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