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Leto [7]
3 years ago
7

What is the volume in milliliter(ml) of 250 cm ^3 beaker

Chemistry
2 answers:
Olenka [21]3 years ago
7 0

Answer:

a cubic centimeter is the same as a millimeter, so it would just be 250ml

lubasha [3.4K]3 years ago
6 0

Answer:

\boxed {\tt 250 \ mL}

Explanation:

First, let's remember that 1 cubic centimeter is equal to 1 milliliter.

  • 1 cm³ = 1 mL

We have a beaker that is 250 cubic centimeters. Since 1 cubic centimeter is equal to 1 milliliter,

  • 250 cm³= 250 mL

The volume in a 250 cm³ beaker is 250 milliliters.

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What is the pOH of a 0.150 M solution of potassium nitrite? (Ka HNO2 = 4.5 x 10−4 )
yanalaym [24]

Answer:

11.9 is the pOH of a 0.150 M solution of potassium nitrite.

Explanation:

Solution :  Given,

Concentration (c) = 0.150 M

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The equilibrium reaction for dissociation of HNO_2 (weak acid) is,

                           HNO_2+H_2O\rightleftharpoons NO_2^-+H_3O^+

initially conc.         c                       0         0

At eqm.              c(1-\alpha)                c\alpha        c\alpha

First we have to calculate the concentration of value of dissociation constant (\alpha ).

Formula used :

k_a=\frac{(c\alpha)(c\alpha)}{c(1-\alpha)}

Now put all the given values in this formula ,we get the value of dissociation constant (\alpha ).

4.5\times 10^{-4}=\frac{(0.150\alpha)(0.150\alpha)}{0.150(1-\alpha)}

4.5\times 10^{-4} - 4.5\times 10^{-4}\alpha =0.150\alpha ^2

0.150\alpha ^2+4.5\times 10^{-4}\alpha-4.5\times 10^{-4}=0

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\alpha=0.0533

No we have to calculate the concentration of hydronium ion or hydrogen ion.

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pH=-\log [H^+]

pH=-\log (0.007995 M)

pH=2.097\approx 2.1

pH + pOH = 14

pOH =14 -2.1 = 11.9

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Explanation:

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Explanation:

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