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Rufina [12.5K]
3 years ago
6

Mutations are more important to the evolution of a species because

Chemistry
1 answer:
EleoNora [17]3 years ago
8 0

Answer: Mutations are important to the evolution of a species because is creates new DNA for a certain gene, creating a new allele.

Hope this helps!!! Good luck!!! ;)

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PLEASE HELP ME URGENT!!! How do i find mass when not given in chemistry
Arisa [49]

Answer:

It depends what other values you have. Can you give more info? If they give density then you can solve for m.

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3 years ago
Consider the heating curve. In which region are most particles moving the fastest?
Nikitich [7]

The particles are moving fastest in Region D) 5.

As temperature increases, so does the average kinetic energy (speed) of the molecules.

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THEY ARE ALL NONMETALS ARE THE CORRECTA NSWER


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Explain the metallic and non metallic behavior of an element based on its position in the periodic table
mash [69]

Answer:

Metallic character refers to the level of reactivity of a metal. Non-metallic character relates to the tendency to accept electrons during chemical reactions. Metallic tendency increases going down a group. Non-metallic tendency increases going from left to right across the periodic table.

Explanation:

7 0
3 years ago
What is the pH of a 1.0 L buffer made with 0.300 mol of HF (Ka = 6.8 × 10⁻⁴) and 0.200 mol of NaF to which 0.150 mol of HCl were
irinina [24]

Answer:

pH = 2.21

Explanation:

Hello there!

In this case, according to the reaction between NaF and HCl as the latter is added to the buffer:

NaF+HCl\rightarrow NaCl+HF

It is possible for us to see how more HF is formed as HCl is added and therefore, the capacity of this HF/NaF-buffer is diminished as it turns acid. Therefore, it turns out feasible for us to calculate the consumed moles of NaF and the produced moles of HF due to the change in moles induced by HCl:

n_{HF}^{new}=0.300mol+0.150mol=0.450mol\\\\n_{NaF}^{new}=0.200mol-0.150mol=0.050mol

Next, we calculate the resulting concentrations to further apply the Henderson-Hasselbach equation:

[HF]=\frac{0.450mol}{1.0L} =0.450M

[NaF]=\frac{0.050mol}{1.0L} =0.050M

Now, calculated the pKa of HF:

pKa=-log(6.8x10^{-4})=3.17

We can proceed to the HH equation:

pH=pKa+log(\frac{[NaF]}{[HF]} )\\\\pH=3.17+log(\frac{0.05M}{0.45M} )\\\\pH=2.21

Best regards!

6 0
3 years ago
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