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OleMash [197]
3 years ago
10

If 13 grams of copper sulfate is reacted with zinc how much of each product is produced?

Chemistry
1 answer:
Sladkaya [172]3 years ago
7 0

Answer:

No. Of Moles of zinc = m/Ar

= 13/ 65.38 = 0.198 moles

From balanced equation, Mole ration between CuSO4 and Zn is 1 : 1

So only 0.198 moles of CuSO4 reacts, it is in excess

Mass = no of Moles X Mr

Mass = 0.198 X 159.5 = 31.59 grams

Volume = mass m denisty

Volume j 31.59 / 3.6 = 8.78 ml

Explanation:

i think this wrong

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Lana balanced an equation so that the result was 2C2H3Br + 5O2 → 4CO2 + 2H2O + 2HBr. Which most likely represents the starting e
seropon [69]

Answer:

C2H3Br + O2 → CO2 + H2O + HBr

Explanation:

The term balancing of chemical reaction equation has a unique meaning in chemistry. What it actually means is to ensure that the number of atoms of each element on the left hand side of reaction equation becomes equal to the number of atoms of the same element on the right hand side of the reaction equation.

When we look at the equation; C2H3Br + O2 → CO2 + H2O + HBr, the number of atoms of each element on the left and right hand sides of the given equation are not the same hence the equation is unbalanced.

If we look at the equation; 2C2H3Br + 5O2 → 4CO2 + 2H2O + 2HBr, the number of atoms of each element on both sides of the reaction equation are now equal, thus the later equation is the balanced version of the former.

6 0
3 years ago
Calculate the pH of a 0.0350M
Triss [41]

Answer:

pH = 12.544

Explanation:

  • NaOH   →    Na+      +     OH-

     0.0350M   0.0350M    0.0350M.........equilibrium

∴ pOH = - log [OH-]

∴ pH + pOH = 14

⇒ [OH-] = 0.0350 M

⇒ pOH = - Log (0.0350)

⇒ pOH = 1.456

⇒ pH = 14 - 1.456

⇒ pH = 12.544

6 0
3 years ago
Read 2 more answers
How many liters of hydrogen gas will be produced at STP from the reaction of 5.159 x 1021 atoms of magnesium with 55.23 g of pho
shtirl [24]

Answer:

0.190L of hydrogen may be produced by the reaction.

Explanation:

Our reaction is:

3Mg + 2H₃PO₄ →  Mg₃(PO₄)₂ + 3H₂

We need to determine the limting reactant. Let's find out the moles of each:

5.159×10²¹ atoms . 1 mol / 6.02×10²³ atoms = 0.00857 moles of Mg

55.23 g . 1 mol / 97.97 g = 0.563 moles of acid

2 moles of acid react to 3 moles of Mg

0.563 moles of acid may react to: (0.563 . 3) /2 = 0.8445 moles of Mg

Definetely the limting reactant is Mg.

As ratio is 3:3, 3 moles of Mg can produce 3 moles of hydrogen

Then, 0.00857 moles of Mg must produce 0.00857 moles of H₂

At STP, 1 mol of any gas occupies 22.4L

0.00857 mol . 22.4L / 1mol = 0.190L

3 0
3 years ago
Can someone help me out
Xelga [282]
Yea the first one my guy
4 0
3 years ago
If measurements of a gas are 100L and 300 kilopascals and then the gas is measured a second time and found to be 75L, describe w
Tanya [424]

Answer:

The pressure of the gas increased (if temperature remained constant).

The Boyle's law supports this observation.

Explanation:

The initial measurements of the gas are given as;

volume = 100 L

Pressure = 300 kpa

The second measurement is given as;

Volume = 75 L

The second reading implies that the volume of the gas has decreased. If the temperature of the gas remained constant, then the pressure must have increased according to the Boyle's law;

At constant temperature, the pressure of a given mass of an ideal gas is inversely proportional to its volume.

4 0
3 years ago
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