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3 years ago

If 13 grams of copper sulfate is reacted with zinc how much of each product is produced?

Chemistry

1 answer:

Sladkaya [172]3 years ago

7 0

Answer:

No. Of Moles of zinc = m/Ar

= 13/ 65.38 = 0.198 moles

From balanced equation, Mole ration between CuSO4 and Zn is 1 : 1

So only 0.198 moles of CuSO4 reacts, it is in excess

Mass = no of Moles X Mr

Mass = 0.198 X 159.5 = 31.59 grams

Volume = mass m denisty

Volume j 31.59 / 3.6 = 8.78 ml

Explanation:

i think this wrong

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3 years ago

A 2.04 g lead weight, initially at 10.8 oC, is submerged in 7.62 g of water at 52.3 oC in an insulated container. clear = 0.128

alisha [4.7K]

Answer: The final temperature of both the weight and the water at thermal equilibrium is $50.26^{o}C$ .

Explanation:

The given data is as follows.

mass = 7.62 g, $T_{2} = 10.8^{o}C$

Let us assume that T be the final temperature. Therefore, heat lost by water is calculated as follows.

q = $mC \times \Delta T$

= $7.62 g \times 4.184 J/^{o}C \times (52.3 - T)$

Now, heat gained by lead will be calculated as follows.

q = $mC \times \text{Temperature change of lead}$

= $2.04 \times 0.128 \times (T - 11.0)$

According to the given situation,

Heat lost = Heat gained

$7.62 g \times 4.184 J/^{o}C \times (52.3 - T)$ = $2.04 \times 0.128 \times (T - 11.0)$

T = $50.26^{o}C$

Thus, we can conclude that the final temperature of both the weight and the water at thermal equilibrium is $50.26^{o}C$ .

7 0

3 years ago

Does anyone know the answers for these

Alexeev081 [22]

Answer: 1. 0.045moles

2. 2.10 grams

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

1. $\text{Number of moles of zinc nitrate}=\frac{8.51g}{189.36g/mol}=0.045moles$

2. Mass of $C_2H_4=moles\times {\text {Molar mass}}=0.075moles\times 28.05g/mol=2.10g$

4 0

3 years ago