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3 years ago

What type of chemical reaction is given by the following balanced equation: Al₂O3 → AL+ O₂

Chemistry

1 answer:

rjkz [21]3 years ago

3 0

Answer:

Decomposition

Explanation:

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What is the mass, in pounds, of 389 mL of a gas that has a density of 1.29 g/L?

devlian [24]

Answer: Mass of gas is 0.001 pounds.

Explanation:

Density is defined as the mass contained per unit volume.

$Density=\frac{mass}{Volume}$

Given : Mass of gas = ?

Density of gas = $1.29g/L$

Volume of gas = 389 ml = 0.389 L (1L=1000ml)

Putting in the values we get:

$1.29g/L=\frac{mass}{0.389L}$

$mass=0.5grams$

$mass=0.5\times 0.002lb=0.001lb$ (1g =0.002 lb)

Thus the mass of gas is 0.001 pounds.

7 0

3 years ago

Need help with this science question..

natali 33 [55]

Answer:no

Explanation:the heat will add more pressureand then it will pop.

5 0

3 years ago

What is the amount in grams of EDTA needed to make 315.1 mL of a 0.05 M EDTA solution. The molar mass of EDTA is 374 g/mol

statuscvo [17]

Answer:

58.92 g EDTA

Explanation:

315.1 mL = .3151 L

M = Moles / Liter

.3151 L x 0.5 mol EDTA x 374 g EDTA = 58.92 g EDTA

1 L EDTA 1 mol EDTA

4 0

2 years ago

What happens to the temperature and density of the material between points B and C?

makvit [3.9K]

Answer:

Temperature decreases and density increases

Explanation:

Let us remember that density of a material increases as the temperature of the material decreases. So the cooler a material becomes, the denser it becomes also.

Between points B and C, the material rapidly cools down and the temperature decreases accordingly. This ultimately results in an increase in density since cooler materials are denser than hot materials.

7 0

3 years ago

How would you prepare 500 mL of 0.360 M solution of CaCl2 from solid CaCl2?

LenKa [72]

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).

$0.500 L \times \frac{0.360mol}{L} = 0.180 mol$

Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).

$0.180 mol \times \frac{110.98g}{mol} = 20.0 g$

To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

You can learn more about solutions here: brainly.com/question/2412491

4 0

1 year ago