Ask question

Ask question

All categories

3 years ago

14

K(x) = 6x + 100 k(-5) =

2 answers:

algol133 years ago

3 0

Answer:

Step-by-step explanation:

Plug the -5 into the x symbol shown in the equation since -5 replaces x:

6(-5) + 100 = 70

DONE!!

larisa [96]3 years ago

3 0

Answer:

<h2>k(-5) = 70</h2>

Step-by-step explanation:

$k(x)=6x+100\\\\k(-5)\to\text{put}\ x=-5\ \text{to}\ k(x):\\\\k(-5)=6(-5)+100=-30+100=70$

You might be interested in

Regina has wet weather on about 3/10 of the days in a year. It has wet weather on about four times as many days as it has fog. O

salantis [7]

I would have to say 4/10. hope this helps

5 0

3 years ago

Irene has a checking account. On Monday she writes a $160 check for groceries. Then she deposits $125 into her account. Finally,

anastassius [24]

First you can see that there are 3 numbers 160,125,and 40 you can add 125 and 40 because they are both checks so then after you add you get $165 in checks do you then subtract $125 which is how much she put in and you get $40. So, she has $-40
In her bank account meaning her back scout was decreased by $40.

3 0

3 years ago

(The question is in the photo)

Naddik [55]

Answer:

6.99

Step-by-step explanation:

11.99+2.99+5.99=20.97

20.97/3=6.99

6 0

2 years ago

Read 2 more answers

Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl

amm1812

Answer:

1. $P(s_1|I)=\frac{1}{11}$

2. $P(s_2|I)=\frac{8}{11}$

3. $P(s_3|I)=\frac{2}{11}$

Step-by-step explanation:

Given information:

$P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3$

$P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1$

(1)

We need to find the value of P(s₁|I).

$P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}$

$P(s_1|I)=\frac{0.015}{0.165}$

$P(s_1|I)=\frac{1}{11}$

Therefore the value of P(s₁|I) is $\frac{1}{11}$ .

(2)

We need to find the value of P(s₂|I).

$P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}$

$P(s_2|I)=\frac{0.12}{0.165}$

$P(s_2|I)=\frac{8}{11}$

Therefore the value of P(s₂|I) is $\frac{8}{11}$ .

(3)

We need to find the value of P(s₃|I).

$P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}$

$P(s_3|I)=\frac{0.03}{0.165}$

$P(s_3|I)=\frac{2}{11}$

Therefore the value of P(s₃|I) is $\frac{2}{11}$ .

4 0

2 years ago

What is 49/25 in a decimal

PSYCHO15rus [73]

49/25 converted into decimal form is
1.96
Hope this helps!

3 0

3 years ago

Read 2 more answers