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kherson [118]
2 years ago
13

Which gas has approximately the same density as c2h6 at stp no nh3 h20 so2?

Chemistry
1 answer:
zmey [24]2 years ago
6 0
1 mole of any gas occupy 22.4 L at STP (standard temperature and pressure, 0°C and 1 atm).

Let given gases be 1 mole. So their volumes will be the same, 22.4 liters.

Density is the ratio of mass to volume.

By formula; density= mass/volume; d=m/V

To find out masses of gases, do the mole calculation.

By formula; mole= mass/molar mass; n= m/M; m= n*M

Molar masses are calculated as
1. C₂H₆ (ethane)                 = 2*12 g/mol + 6*1 g/mol= 30 g/mol
2. NO (nitrogen monoxide) = 1*14 g/mol + 1*16 g/mol= 30 g/mol
3. NH₃ (ammonia)              = 1*14 g/mol + 3*1 g/mol= 17 g/mol
4. H₂O (water)                    = 2*1 g/mol + 1*16 g/mol= 18 g/mol
5. SO₂ (sulfur dioxide)        = 1*32 g/mol + 2*16 g/mol= 64 g/mol
Use Periodic Table to get atomic mass of elements.

Since their volumes are equal, compounds having the same molar mass will have the same density. 
Recall the formula d= m/V.

Ethane and nitrogen monoxide have the same density.

The answer is C₂H₆ and NO.
You might be interested in
A gas at 127०C and 10.0 L expands to 20.0 L. What is the new temperature in Celcius? (HINT: You need to convert to Kelvins solve
Snowcat [4.5K]

Answer:

526.85K

Explanation:

Based on Charles's law, the volume of a gas is directly proportional to absolute temperature. The formrula is:

V₁ / T₁ = V₂ / T₂

<em>Where 1 represents the initial state and 2 the final state of the gas</em>

Using the values of the problem:

V₁ = 10.0L

T₁ = 127°C + 273.15K = 400.15K

V₂ = 20.0L

Thus, replacing in the formula:

10.0L / 400.15K = 20.0L / T₂

T₂ = 800K

In Celsius:

800K - 273.15 =<em> 526.85K</em>

<em />

3 0
3 years ago
Different kinds of light are all around us everyday, but we are invisible to it. Explain the type of light that is visible to hu
belka [17]

Answer:

The human eye can only see white visible light and it contains all the colors of the rainbow, from red to violet.

Explanation:

But visable light comes in many "colors" such as radio, infrared, ultraviolet, X-ray, and gamma-ray that are invisible to the naked eye.The reason that the human eye can see the spectrum is because those specific wavelengths stimulate the retina in the human eye.

8 0
3 years ago
Where is the color rock located?
ludmilkaskok [199]
Ans: The fluorescent-colored rock stacks rise from the desert floor more than 20 miles south of the Las Vegas Strip. Crafted from local limestone, the boulders were painted in fluorescent hues before being stacked. The towers are between 25 and 35 feet tall.
3 0
2 years ago
How many moles of aqueous potassium ions and sulfate ions are formed when 63.7 g of K2SO4 dissolves in water
Viefleur [7K]

Answer:

WHEN 63.7 g OF K2SO4 IS DISSOLVED IN WATER, 0.73 MOLES OF POTASSIUM ION AND 0.366 MOLES OF SULFATE ION ARE FORMED.

Explanation:

Equation for the reaction:

K2SO4 + H20 ------->2 K+ + SO4^2-

When K2SO4 dissolves in water, potassium ion and sulfate ion are formed.

1 mole of K2SO4 produces 2 moles and 1 mole of SO4^2-

At STP, 1 mole of K2SO4 will be the molar mass of the substance

Molar mass of K2SO4 = ( 39 *2 + 32 + 16*4) g/mol

Molar mass = 174 g/mol

So therefore;

1 mole of K2SO4 contains 174 g and it produces 2 moles of potassium and 1 mole of sulfate ion

When 63.7 g is used; we have:

174 g = 2 moles of K+

63.7 g = ( 63.7 * 2 / 174) moles of K+

= 0.73 moles of K+

Forr sulfate ion, we have:

174 g = 1 mole ofSO4^2-

63.7 g = (63.7 * 1 / 174) moles of SO4^2-

= 0.366 moles of SO4^2-

In other words, when 63.7 g of K2SO4 is dissolved in water, 0.73 moles of potassium ion and 0.366 moles of sulfate ion are formed.

4 0
3 years ago
The solubility of N2 in water at a particular temperature and at a N2 pressure of 1 atm is 6.8 × 10–4 mol L–1. Calculate the con
grin007 [14]

Answer:

The correct answer is 5.30 * 10^-4 mol per L.

Explanation:

Based on Henry's law, in a solution solubility of the gas is directly proportional to the pressure, that is, C is directly proportional to P. Here P is the pressure and C is the concentration of the dissolved gases.  

Therefore, it can be written as,  

C2/C1 = P2/P1

Here, C1 is 6.8 * 10^-4 mol/L, P1 is 1 atm and P2 is 0.78 atm, then the value of C2 obtained by putting the values in the equation,  

C2/(6.8*10^-4) = 0.78/1

C2 = 0.78 * 6.8*10^-4

C2 = 5.30 * 10^-4 mol per L.  

Hence, the concentration of dissolved nitrogen at 0.78 atm is 5.30*10^-4 mol/L.  

7 0
2 years ago
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