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ella [17]
2 years ago
10

What volume of the 5.00% (w/v) citrie acid solution described above would be needed to provide 738 mg citric acid for a reaction

?
738 mg of eitrie acid for a reaction Show your work using dimensional analysis and report yo
answer with the correct number of significant figures, (You should know the relationship betw
grams and milligrams.)
Chemistry
1 answer:
aliya0001 [1]2 years ago
4 0

Answer:

V=14.76mL

Explanation:

Hello!

In this case, since the given 5.00 % (w/v) can also be represented in terms of mass of solute over volume of solution, we need to make sure that the same system of units is used, in this case, the appropriate units for that unit of concentration should be g/mL, and therefore, we first need the mass of citric acid in grams:

m=738mg*\frac{1g}{1000mg} =0.738 g

Thus, by using the w/v percent, we obtain the following volume of solution:

V=\frac{m}{m/w}*100\%

So we plug in to obtain:

V = \frac{0.738g}{5.00\%}*100\% \\\\V=14.76mL

Best regards!

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The density of a rectangle : ρ = 0.372 g/cm³

<h3>Further explanation</h3>

Given

The volume of rectangle : 395 cm³

Mass : 147 g

Required

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Solution

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

Density formula:  

\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}

ρ = density  

m = mass  

v = volume

Input the value :

ρ = 147 g : 395 cm³

ρ = 0.372 g/cm³

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