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ella [17]
3 years ago
10

What volume of the 5.00% (w/v) citrie acid solution described above would be needed to provide 738 mg citric acid for a reaction

?
738 mg of eitrie acid for a reaction Show your work using dimensional analysis and report yo
answer with the correct number of significant figures, (You should know the relationship betw
grams and milligrams.)
Chemistry
1 answer:
aliya0001 [1]3 years ago
4 0

Answer:

V=14.76mL

Explanation:

Hello!

In this case, since the given 5.00 % (w/v) can also be represented in terms of mass of solute over volume of solution, we need to make sure that the same system of units is used, in this case, the appropriate units for that unit of concentration should be g/mL, and therefore, we first need the mass of citric acid in grams:

m=738mg*\frac{1g}{1000mg} =0.738 g

Thus, by using the w/v percent, we obtain the following volume of solution:

V=\frac{m}{m/w}*100\%

So we plug in to obtain:

V = \frac{0.738g}{5.00\%}*100\% \\\\V=14.76mL

Best regards!

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2 years ago
You use a balance to find the mass of a folded newspaper. Then you run it through a shredder. Predict its mass after being shred
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Bello,

I think the answer is A

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3 years ago
Percent of water in Na2CO3 • 10H2O
Troyanec [42]
Hey there! 

In order to solve for the percentage of water in the compound, you will first need to find its total molar mass. You can do this by adding up the molar masses of each individual element in the compound. Then, you will divide the mass that you find of the water molecules by the total mass to get the percentage. 

→ Na₂CO₃ ×<span> 10 H</span>₂<span>O

</span>→ Na₂ = 22.9898 × 2 = 45.9796
→ C = 12.0107
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Now, just add all of those numbers up for the total molar mass. 

→ 45.9796 + 12.0107 + 47.997 + 180.15 = <span>286.1373
</span>
The last step is to divide the molar mass of the 10 water molecules by the total mass. 

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Your answer will be about 63%. 

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Read 2 more answers
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