A chemist is using a solution of HNO₃ that has a pH of 3.75. what is [H⁺] for the solution is 1.7 × 10⁻⁴M.
<h3>How do we calculate the [
H⁺]?</h3>
Concentration of H⁺ ion will be calculated by using the below equation of pH as:
pH = -log[H⁺]
or [H⁺] = 
Given that, pH = 3.75
So concentration of H⁺ ion will be calculated as:
[H⁺] = 
[H⁺] = 1.7 × 10⁻⁴M
Hence concentration of H⁺ ion is 1.7 × 10⁻⁴M.
To know more about pH & [H⁺], visit the below link:
brainly.com/question/8758541
It gives off a certain colour because when the spectrum is combined........I'm not sure if that's write but i think it is.....not 100% sure tho
Answer:
Kc = [C2H5OH]/{[C2H4][H2O]}
[H2O] = [C2H5OH]/{[C2H4] x Kc}
[H2O] = 1.69/(0.015 x 9.0 x 10^3) = 0.013 M
Explanation:
Kc is the equilibrium constant, it is egal to the product of the equilibrium concentration of the product dived by the product of the equilibrium concentration of the reactants.
with that formula and what is given, male the equilibrium concentration of H2O the subject of the formula and calculate its concentration by substituting given values.
Answer:
C5H6N2O3
Explanation:
First the empirical formulas
C= 41.8÷12= 2.48
H= 4.7÷1= 4.7
O= 37.3÷ 16= 2.33
N= 16.3÷14 = 1.16
Divide by the smallest
C= 3.48/1.16=3
H= 4.7/1.16=4.1
O= 2.33/1.16=2
N= 1.16/1.16=1
Therefore empirical formula = C3H4NO2
To calculate molecular formula for osmotic pressure,
π= cRT
Or
π=cgRT/M where cg is in g/liter & T is temperature in Kelvin. Thus
π= (7.480*0.0821*300)/ M
M= 184.23/1.43
M= 128.83
To find molecular Formula
Molecular Mass= (empirical mass)n
128.83= (C3H4NO2)n
128.83= 86n
n= 1.5
Therefore the molecular formula
(C3H4NO2)1.5
= C4.5H6N1.5O3
Approximately
C5H6N2O3