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vagabundo [1.1K]
3 years ago
5

What changes in airplane longitudinal control must be made to maintain altitude while the airspeed is being decreased?

Physics
1 answer:
garik1379 [7]3 years ago
8 0

Explanation:

The  changes can be made in airplane longitudinal control to maintain altitude while the airspeed is being decreased is

We can increase the angle of attack this would compensate for the decreasing lift. As the angle of attack directly controls the distribution of pressure on the wings. Moreover, increase in angle of attack will also cause the drag to increase.

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Once a baseball has been hit into the air, what forces are acting upon it? How can you tell that any forces are acting upon the
Tom [10]
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Two students race up a flight of steps together. "Student A" reaches the top of the steps 2 seconds ahead of
oksano4ka [1.4K]
Um student a because they were there a few seconds ahead
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3 years ago
After getting a haircut, Joey’s barber spins him around in his barber’s chair 2 times per second. Is period or frequency given?
Rzqust [24]

Answer:

Explanation:

This figure given is the frequency; 2 times per second represents frequency.

What is frequency?

  • It is the number of times per seconds something goes past or around another.

 it is expressed as:

            Frequency  = \frac{n}{t}

                  where n is the number of turns

                              t is the time taken

  Therefore, the Barber spinned him 2 times in 1 second.

The period is the inverse of frequency. It is the time taken for a body to go through a point;

              Period  = \frac{t}{n }   = \frac{1}{f}    = \frac{1}{2}s

7 0
3 years ago
Dimension equation of work
kkurt [141]

Answer:

Explanation:

Work

Other units Foot-pound, Erg

In SI base units 1 kg⋅m2⋅s−2

Derivations from other quantities W = F ⋅ s W = τ θ

Dimension M L2 T−2

Idk if this is what u are looking for but i hope this help.:)

3 0
3 years ago
A satellite at a particular point along an elliptical orbit has a gravitational potential energy of 5100 MJ with respect to Eart
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To solve this problem we will apply the theorem given in the conservation of energy, by which we have that it is conserved and that in terms of potential and kinetic energy, in their initial moment they must be equal to the final potential and kinetic energy. This is,

E_{initial} = E_{final}

PE_{initial}+KE_{initial} = PE_{final}+KE_{final}

Replacing the 5100MJ for satellite as initial potential energy, 4200MJ for initial kinetic energy and 5700MJ for final potential energy we have that

KE_{final} = (PE_{initial}+KE_{initial} )-PE_{final}

KE_{final} = (5100+4200)-5700

KE_{final} = 3600MJ

Therefore the final kinetic energy is 3600MJ

5 0
3 years ago
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