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vagabundo [1.1K]
3 years ago
5

What changes in airplane longitudinal control must be made to maintain altitude while the airspeed is being decreased?

Physics
1 answer:
garik1379 [7]3 years ago
8 0

Explanation:

The  changes can be made in airplane longitudinal control to maintain altitude while the airspeed is being decreased is

We can increase the angle of attack this would compensate for the decreasing lift. As the angle of attack directly controls the distribution of pressure on the wings. Moreover, increase in angle of attack will also cause the drag to increase.

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A rocket with a mass of 62,000 kg (including fuel) is burning fuel at the rate of 150 kg/s and the speed of the exhaust gases is
mezya [45]

Answer:

h≅ 58 m

Explanation:

GIVEN:

mass of rocket M= 62,000 kg

fuel consumption rate =  150 kg/s

velocity of exhaust gases v= 6000 m/s

Now thrust = rate of fuel consumption×velocity of exhaust gases

=6000 × 150 = 900000 N

now to need calculate time t = amount of fuel consumed÷ rate

= 744/150= 4.96 sec

applying newton's law

M×a= thrust - Mg

62000 a=900000- 62000×9.8

acceleration a= 4.71 m/s^2

its height after 744 kg of its total fuel load has been consumed

h= \frac{1}{2}at^2

h= \frac{1}{2}4.71\times4.96^2

h= 58.012 m

h≅ 58 m

4 0
3 years ago
The distance and displacement of a object in motion can be the same (true or false)
Rasek [7]

Aswer:

False, the values ​​of the distance traveled and the displacement only coincide when the trayectorie is a straight line. Otherwise, the distance will always be greater than the offset.

Although these terms are used synonymously in other cases, they are totally different. Since the distance that a mobile travels is the equivalent of the length of its trajectory. Whereas, the displacement will be a vector magnitude.

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4 0
3 years ago
why did scientists using classical, newtonian physics have difficulty explaining the photoelectric effect
zzz [600]

The correct answer is :

According to classical electrodynamics, light energy is a wave that is absorbed by atoms in a manner similar to how an object absorbs radiant heat. So, the atoms of a metal would absorb more energy the brighter the light was. It would be feasible for an electron in a metal to break free from its atoms if it received enough energy from the incoming wave. The more energy absorbed, the more energetic the metal's released electrons would be. Additionally, no electrons could conceivably be ejected until each atom had enough light energy. Light intensity was far more important than light frequency.

In many respects, the photo-electric effect contradicted this strategy:

  • If the light was below a specific frequency, no matter how bright it was, no electrons were released. Increased light intensity increased the number of electrons that were released, but not their energy, if the light was above this frequency.
  • Regardless of how weak the light was, electrons were nearly immediately emitted from the metal.
  • Even though the intensity of the light was reduced, an increase in its frequency led to more energising electrons leaving the metal.

To learn more about photo-electric effect refer the link:

brainly.com/question/25630303

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7 0
1 year ago
According to Newton's second law, force is equal to ______________.
Svetach [21]
Hey there!
The Second Law of Motion by Newton is f = ma, and that means the force of an object is defined by its mass times its acceleration.
Therefore your answer is e.
Hope this helps!
3 0
3 years ago
Read 2 more answers
How does the coulomb force affect charge interactions.
dalvyx [7]

Answer: According to Coulomb, the electric force for charges at rest has the following properties: Like charges repel each other; unlike charges attract. Thus, two negative charges repel one another, while a positive charge attracts a negative charge. The attraction or repulsion acts along the line between the two charges.

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8 0
3 years ago
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