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Monica [59]
1 year ago
13

Jupiter has enough mass to make 318 earths. In contrast, uranus and neptune have only enough mass to make.

Physics
1 answer:
Bezzdna [24]1 year ago
6 0

Uranus and Neptune have only enough mass to make <u>Option c. 15 piles of earth</u>

<u />

Jupiter is the fifth planet from the sun and the largest within the sun gadget. it is a fuel massive with a mass greater than two and a half of instances that of all of the other planets inside the solar machine combined, but barely much less than one-thousandth the mass of the solar.

Uranus is the 7th planet from the sun. Its call is a connection with the Greek god of the sky, Uranus, who, according to Greek mythology, became the exquisite grandfather of Ares, grandfather of Zeus, and father of Cronus. It has the 1/3-largest planetary radius and the fourth-largest planetary mass within the sun machine.

Learn more about Jupiter here:-brainly.com/question/15044627

#SPJ4

Disclaimer:- your question is incomplete, please see below for the complete question.

Jupiter has enough mass to make 318 earths. In contrast, uranus and Neptune have only enough mass to make.

a. 100 Earths

b. 70 Earths

c. 15 Earths

d. 2 Earths

e. you can't fool me, Uranus and Neptune have a lot of ice, and so have much more mass than Jupiter

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Concrete colums are constructed with reinforcing steel in them to make them stronger and more ductile. The reinforcing bars are
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Answer:

21678.47223\ lbf-in^2

383.1109\ lbf-in^2

Explanation:

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\dfrac{F_sL}{A_sE_s}=\dfrac{F_cL}{A_cE_c}\\\Rightarrow F_c=\dfrac{F_sA_cE_c}{A_sE_s}\\\Rightarrow F_c=\dfrac{F_s \times 119.4\times 4.1\times 10^6}{8\times \dfrac{\pi \dfrac{1}{2^2}}{4}\times 29\times 10^6}\\\Rightarrow F_c=10.74658F_s

Now

F_c+F_s=50000\\\Rightarrow 10.74658F_s+F_s=50000\\\Rightarrow F_s=\dfrac{50000}{11.74658}\\\Rightarrow F_s=4256.55807\ lbf

F_c=10.74658F_s\\\Rightarrow F_c=10.74658\times 4256.55807\\\Rightarrow F_c=45743.44182\ lbf

Stress is given by

\sigma_s=\dfrac{4256.55807}{\pi \dfrac{1}{2^2}}{4}\\\Rightarrow \sigma_s=21678.47223\ lbf-in^2

The stress in the steel is 21678.47223\ lbf-in^2

\sigma_c=\dfrac{45743.44182}{119.4}\\\Rightarrow \sigma_s=383.1109\ lbf-in^2

The stress in the steel is 383.1109\ lbf-in^2

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