All categories

1 year ago

Jupiter has enough mass to make 318 earths. In contrast, uranus and neptune have only enough mass to make.

Physics

1 answer:

Bezzdna [24]1 year ago

6 0

Uranus and Neptune have only enough mass to make Option c. 15 piles of earth

Jupiter is the fifth planet from the sun and the largest within the sun gadget. it is a fuel massive with a mass greater than two and a half of instances that of all of the other planets inside the solar machine combined, but barely much less than one-thousandth the mass of the solar.

Uranus is the 7th planet from the sun. Its call is a connection with the Greek god of the sky, Uranus, who, according to Greek mythology, became the exquisite grandfather of Ares, grandfather of Zeus, and father of Cronus. It has the 1/3-largest planetary radius and the fourth-largest planetary mass within the sun machine.

Learn more about Jupiter here:-brainly.com/question/15044627

#SPJ4

Disclaimer:- your question is incomplete, please see below for the complete question.

Jupiter has enough mass to make 318 earths. In contrast, uranus and Neptune have only enough mass to make.

a. 100 Earths

b. 70 Earths

c. 15 Earths

d. 2 Earths

e. you can't fool me, Uranus and Neptune have a lot of ice, and so have much more mass than Jupiter

You might be interested in

If the mess of an object______, the weight of an object will _______

Gnom [1K]

Answer:

the same

Explanation:

7 0

2 years ago

____ is a measure of electric potential energy ampere coulomb ohm volt

Drupady [299]

The answer is volt for this question.

I hope is correct if not I’m sorry.

6 0

3 years ago

Concrete colums are constructed with reinforcing steel in them to make them stronger and more ductile. The reinforcing bars are

Sergio039 [100]

Answer:

$21678.47223\ lbf-in^2$

$383.1109\ lbf-in^2$

Explanation:

d = Diameter of column = 0.5 inch

$A_c$ = Area of concrete = $119.4\ in^2$

The strain in the system is conserved

$\dfrac{F_sL}{A_sE_s}=\dfrac{F_cL}{A_cE_c}\\\Rightarrow F_c=\dfrac{F_sA_cE_c}{A_sE_s}\\\Rightarrow F_c=\dfrac{F_s \times 119.4\times 4.1\times 10^6}{8\times \dfrac{\pi \dfrac{1}{2^2}}{4}\times 29\times 10^6}\\\Rightarrow F_c=10.74658F_s$

Now

$F_c+F_s=50000\\\Rightarrow 10.74658F_s+F_s=50000\\\Rightarrow F_s=\dfrac{50000}{11.74658}\\\Rightarrow F_s=4256.55807\ lbf$

$F_c=10.74658F_s\\\Rightarrow F_c=10.74658\times 4256.55807\\\Rightarrow F_c=45743.44182\ lbf$

Stress is given by

$\sigma_s=\dfrac{4256.55807}{\pi \dfrac{1}{2^2}}{4}\\\Rightarrow \sigma_s=21678.47223\ lbf-in^2$

The stress in the steel is $21678.47223\ lbf-in^2$

$\sigma_c=\dfrac{45743.44182}{119.4}\\\Rightarrow \sigma_s=383.1109\ lbf-in^2$

The stress in the steel is $383.1109\ lbf-in^2$

4 0

3 years ago

Why can television satellites, which broadcast information as electromagnetic radiation, send signals from the vacuum of space?

neonofarm [45]

The answer is b. Electromagnetic waves do not need a medium to travel through.

5 0

2 years ago

Read 2 more answers

Co (5. 00 g) and co2 (5. 00 g) were placed in a 750. 0 ml container at 50. 0 °c. The partial pressure of co in the container was

konstantin123 [22]

Use PV = nRT and solve for P.
n = grams/molar mass = 5.00/molar mass CO2
Ignore the SO2.

But I think the answer it 6.74 atm

But I’m not saying but is but I’m just thinking this is the answer.

Goodluck!

6 0

2 years ago