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Monica [59]
1 year ago
13

Jupiter has enough mass to make 318 earths. In contrast, uranus and neptune have only enough mass to make.

Physics
1 answer:
Bezzdna [24]1 year ago
6 0

Uranus and Neptune have only enough mass to make <u>Option c. 15 piles of earth</u>

<u />

Jupiter is the fifth planet from the sun and the largest within the sun gadget. it is a fuel massive with a mass greater than two and a half of instances that of all of the other planets inside the solar machine combined, but barely much less than one-thousandth the mass of the solar.

Uranus is the 7th planet from the sun. Its call is a connection with the Greek god of the sky, Uranus, who, according to Greek mythology, became the exquisite grandfather of Ares, grandfather of Zeus, and father of Cronus. It has the 1/3-largest planetary radius and the fourth-largest planetary mass within the sun machine.

Learn more about Jupiter here:-brainly.com/question/15044627

#SPJ4

Disclaimer:- your question is incomplete, please see below for the complete question.

Jupiter has enough mass to make 318 earths. In contrast, uranus and Neptune have only enough mass to make.

a. 100 Earths

b. 70 Earths

c. 15 Earths

d. 2 Earths

e. you can't fool me, Uranus and Neptune have a lot of ice, and so have much more mass than Jupiter

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Suppose a certain car supplies a constant deceleration of A meter per second per second. If it is traveling at 90km/hr. When. th
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Answer:

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ii)18 metres

iii)26.5 m/s or 95.4 km/hr

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Firstly convert 90km/hr to m/s

90 × 1000/3600 = 25m/s

(i) Apply v^2 = u^2 + 2As...where v(0m/s) is the final speed and u(25m/s) is initial speed and also s is the distance moved through(50 metres)

0 = (25)^2 + 2A(50)

0 = 625 + 100A....then moved the other value to one

-625 = 100A

Hence A = -6.25m/s^2(where the negative just tells us that its deceleration)

(ii) Firstly convert 54km/hr to m/s

In which this is 54 × 1000/3600 = 15m/s

then apply the same formula as that in (i)

0 = (15)^2 + 2(-6.25)s

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Hence the stopping distance = 18metres

(iii) Apply the same formula and always remember that the deceleration values is the same throughout this question

0 = u^2 + 2(-6.25)(56)

u^2 = 700

Hence the speed that the car was travelling at is the,square root of 700 = 26.5m/s

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