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1 year ago

Jupiter has enough mass to make 318 earths. In contrast, uranus and neptune have only enough mass to make.

Physics

1 answer:

Bezzdna [24]1 year ago

6 0

Uranus and Neptune have only enough mass to make Option c. 15 piles of earth

Jupiter is the fifth planet from the sun and the largest within the sun gadget. it is a fuel massive with a mass greater than two and a half of instances that of all of the other planets inside the solar machine combined, but barely much less than one-thousandth the mass of the solar.

Uranus is the 7th planet from the sun. Its call is a connection with the Greek god of the sky, Uranus, who, according to Greek mythology, became the exquisite grandfather of Ares, grandfather of Zeus, and father of Cronus. It has the 1/3-largest planetary radius and the fourth-largest planetary mass within the sun machine.

Learn more about Jupiter here:-brainly.com/question/15044627

#SPJ4

Disclaimer:- your question is incomplete, please see below for the complete question.

Jupiter has enough mass to make 318 earths. In contrast, uranus and Neptune have only enough mass to make.

a. 100 Earths

b. 70 Earths

c. 15 Earths

d. 2 Earths

e. you can't fool me, Uranus and Neptune have a lot of ice, and so have much more mass than Jupiter

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Two moles of neon gas at 25oC and 2.0 atm is expanded to 3 times the original volume while the pressure is reduced to 1.0 atm. F

bazaltina [42]

Answer:

The end temperature is 174 °C

Explanation:

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

So, being:

P= 2 atm
V=?
n= 2 moles
R= 0.082 $\frac{atm*L}{mol*K}$
T= 25 °C= 298 °K

and replacing:

2 atm*V= 2 moles* 0.082 $\frac{atm*L}{mol*K}$ *298 K

you get:

$V=\frac{2 moles* 0.082\frac{atm*L}{mol*K} *298 K}{2 atm}$

V= 24.436 L

Now, two moles of neon gas is expanded to 3 times the original volume while the pressure is reduced to 1.0 atm. Then you know:

P= 1 atm
V= 3*24.436 L=73.308 L

n= 2 moles
R= 0.082 $\frac{atm*L}{mol*K}$
T= ?

Replacing:

1 atm*73.308 L= 2 moles* 0.082 $\frac{atm*L}{mol*K}$ *T

Solving:

$T=\frac{1 atm*73.308 L}{2 moles* 0.082\frac{atm*L}{mol*K}}$

T= 447 °K= 174 °C (being 0°C=273 °K)

The end temperature is 174 °C

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A spherical wave with a wavelength of 2.0 mm is emitted from the origin. At one instant of time, the phase at rrr = 4.0 mm is πr

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Complete Question

A spherical wave with a wavelength of 2.0 mm is emitted from the origin. At one instant of time, the phase at r_1 = 4.0 mm is π rad. At that instant, what is the phase at r_2 = 3.5 mm ? Express your answer to two significant figures and include the appropriate units.

Answer:

The phase at the second point is $\phi _2 = 1.57 \ rad$