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kifflom [539]
3 years ago
13

Angular Velocity The Moon rotates once on its axis in 27.3 days. Its radius is 27.3 days

Physics
1 answer:
dolphi86 [110]3 years ago
5 0
B is the answer I’m sure
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dolphi86 [110]

Answer:

I thinks its a, but its really about gravity im not sure

Explanation:

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3 years ago
Which describes a p-type semiconductor?
Digiron [165]
It has holes (an electron deficiency).
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A 30.4-newton force is used to slide a 40.0-newton crate a distance of 6.00 meters at constant speed along an incline to a verti
Angelina_Jolie [31]

Hi there!

Since the crate is being slid at a constant speed, the forces sum to 0 N. In this instance, the following forces occur in the axis of interest:

Wsinθ = downward acceleration along incline due to gravity (N)

Fκ = kinetic friction force along incline (N)

A = applied force (N)

The acceleration due to gravity and friction force act in the same direction, so:

Wsinθ + Fκ = A

Solve for sinθ using right triangle trigonometry:

sinθ = O/H = 3/6 = 0.5

Rearrange the equation for the force of kinetic friction and solve:

Fκ = A - 0.5W

Fκ = 30.4 - 20 = 10.4 N

Now, recall that:

Work = Force × displacement (W = F × d)

Since the box's displacement is in the same axis as the force but OPPOSITE direction, we must use:

W = Fdcosθ

Angle between displacement and friction force is 180°.

cos(180) = -1

Work done by friction = -Fd = -10.4(6) = -62.4 J

8 0
3 years ago
Aconstant current of 3 Afor 4 hours is required to charge an automotive battery. If the terminal voltage is V, where t is in hou
kirza4 [7]

Answer:

(a) 43.2 kC

(b) 0.012V kWh

(c) 0.108V cents

Explanation:

<u>Given:</u>

  • i = current flow = 3 A
  • t = time interval for which the current flow = 4\ h = 4\times 3600\ s = 14400\ s
  • V = terminal voltage of the battery
  • R = rate of energy = 9 cents/kWh

<u>Assume:</u>

  • Q = charge transported as a result of charging
  • E = energy expended
  • C = cost of charging

Part (a):

We know that the charge flow rate is the electric current flow through a wire.

\therefore i = \dfrac{Q}{t}\\\Rightarrow Q =it\\\Rightarrow Q = 3\times 14400\\\Rightarrow Q = 43200\ C\\\Rightarrow Q = 43.200\ kC\\

Hence, 43.2 kC of charge is transported as a result of charging.

Part (b):

We know the electrical energy dissipated due to current flow across a voltage drop for a time interval is given by:

E = Vit\\\Rightarrow E = V\times 3\times 4\\\Rightarrow E = 12V\ Wh\\\Rightarrow E = 0.012V\ kWh\\

Hence, 0.012V kWh is expended in charging the battery.

Part (c):

We know that the energy cost is equal to the product of energy expended and the rate of energy.

\therefore \textrm{Cost}=\textrm{Energy}\times \textrm{Rate}\\\Rightarrow C = ER\\\Rightarrow C = 0.012V\times 9\\\Rightarrow C =0.108V\ cents

Hence, 0.108V cents is the charging cost of the battery.

4 0
4 years ago
The rainforest is hot, humid, and has frequent rainfall. In what way do the atmosphere and the hydrosphere contribute to this ty
il63 [147K]

Answer:

The atmosphere which contains nitrogen, oxygen, carbon dioxide, and other gases essential for life, contributes to the rainforest climate. The rainforest is hot, humid and helps balance the amount of carbon dioxide in the atmosphere by absorbing it and releasing more oxygen which is important for climate change.

The hydrosphere, which is the combination of various types of water sources and types found in air, in the form of water vapor; water found below the earth's surface and above, also contributes to the rainforest climate. The frequent rainfall dictates the vegetation growth in that area which also creates weather patterns due to the contribution of the atmosphere and the hydrosphere. The hydrosphere is important in the formation of rain. A  rainforest of frequent rainfall indicates a large amount of the combination of various types of water sources and types found in a particular area, which release the water back onto the rainforest.

7 0
3 years ago
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