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kifflom [539]
3 years ago
13

Angular Velocity The Moon rotates once on its axis in 27.3 days. Its radius is 27.3 days

Physics
1 answer:
dolphi86 [110]3 years ago
5 0
B is the answer I’m sure
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Estimate the magnitude of the electric field due to the proton in a hydrogen atom at a distance of
Lana71 [14]

Electric field due to a point charge is given as

E = \frac{kq}{r^2}

here we know that

q = 1.6 \times 10^{-19} C

also the distance is given as

r = 5.29 \times 10^{-11} m

now we will have

E = \frac{(9\times 10^9)(1.6 \times 10^{-19})}{(5.29 \times 10^{-11})^2}

so we will have

E = 5.14 \times 10^{11} N/C

so above is the electric field due to proton

5 0
3 years ago
How could you increase the kinetic energy of a wagon without increasing it's mass
Zarrin [17]

Answer:

send the wagon down a higher hill

3 0
3 years ago
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A stuntman jumps from the roof of a building to the safety net below. How far has the stuntman fallen after 1.6 seconds?
Fantom [35]
How tall is the building?
u need to divide the height by 1.6 to get your answer
6 0
3 years ago
a ball is shot from the ground straight up into the air with initial velocity of 50 50 ft/sec. assuming that the air resistance
Anna [14]

The height attained by the ball is 11.86m

a ball is shot from the ground straight up into the air its initial and final velocity is

initial velocity, u = 50 ft/s = 50×0.305  = 15.25m/s

final velocity ,v = 0 m/s

gravity =-9.8 m/s²

( negative sign shows acceleration in opposite direction)

height =?

using the newton motion of equation

v² = u² + 2as

where

a= acceleration due to gravity(g)

s = height

v² = u² + 2gs

(0)² = (15.25)² + 2×(-9.8)×s

0  = (15.25)² -  19.6 × s

s= - (15.25)²/ 19.6

s = 11.86m

after ignoring the air resistance the maximum height of the ball is 11.86m

To learn more about motion under gravity -

brainly.com/question/27962354

#SPJ4

3 0
1 year ago
During a thunderstorm a tornado lift a car to a height of 300 m above the ground increasing and strength the tornado flings the
sasho [114]

Answer:

Explanation:

To calculate the time it took the car to hit the ground, we use the formula

speed = distance/time

80 m/s = 300 m/time

time = 300/80

time = 3.75 secs

It must have taken the car 3.75 seconds to hit the ground

To determine the horizontal distance of the car before hitting the ground, the same formula will also be used but with the time obtained above (since that was the time it took before hitting the ground)

speed = distance/time

80 = distance/3.75

distance = 3.75 x 80

distance = 300 meters

4 0
3 years ago
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