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Iteru [2.4K]
3 years ago
14

A stone is thrown into a well and the splash is heard after 3s. (speed of sound : 340m/s) . 1.) What time did the stone take to

reach the water? 2.) how long did it take for the sound to reach the observer? 3.) What is the depth of the well ?
P.s this question was super difficult for me even my physics teacher couldnt do it ( I know it's a shame) but I'm giving 50 points , so geeks start solving.
Physics
1 answer:
miss Akunina [59]3 years ago
8 0
1.)3s
2.)6s
3.)1020m

hope this help
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Consider a book that weighs 15 N at rest on a flat table. How many newtons of support does the table provide?
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<span>The support force is 15 N. The net force on the book is zero.</span>
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a distant galaxy is studied with a radio telescope x ray telescope and optical light telescope. the images form which set of mus
aivan3 [116]

Answer:

The modern instruments or we can say the different levels of telescopes are used to explore and study the distant galaxies. i.e the Hubble telescope is out there providing the data regarding the different properties of the celestial entities which in other case is not visible to the human naked eye.

Explanation:

  • Scientists and research workers are in constant search for more answers as they explore the universe and implement the laws of physics on the celestial entities. But, most of the objects inside the universe are not visible to human naked eye, as they are far from sight and thus more advanced form of instruments like the x-ray, optical, and light telescopes are used to determine the different properties of the celestial entities inside the universe.
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6 0
3 years ago
A 6 kg box with initial speed 5 m/s slides across the floor and comes to a stop after 1.9 s. What is the coefficient of kinetic
Ilia_Sergeevich [38]

Answer:

\mu_k=0.27

Explanation:

According to the free body diagram, in this case, we have:

\sum F_x:-F_k=ma\\\sum F_y:N=mg

Recall that the force of friction is given by:

F_k=\mu_k N

Replacing and solving for the coefficient of kinetic friction:

-\mu_kN=ma\\-\mu_k(mg)=ma\\\mu_k=-\frac{a}{g}

We have an uniformly accelerated motion. Thus, the acceleration is defined as:

a=\frac{v_f-v_0}{t}\\a=\frac{0-5\frac{m}{s}}{1.9s}\\a=-2.63\frac{m}{s^2}

Finally, we calculate \mu_k:

\mu_k=-\frac{-2.63\frac{m}{s^2}}{9.8\frac{m}{s^2}}\\\mu_k=0.27

4 0
3 years ago
An airplane is flying in the direction 10° east of south at 701 km/hr. Find the component form ofthe velocity of the airplane, a
solniwko [45]

Answer:

The component form will be;

In the x-axis = 121.73 due west

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Explanation:

An image of the calculation has been attached

7 0
2 years ago
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WINSTONCH [101]

Answer:

2.000.000.000

Explanation:

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I think it is that, can be wrong.

7 0
3 years ago
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