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yan [13]
3 years ago
7

A concave mirror is used to ______ ( converge, diverge) light and a convex mirror is used to _____( diverge or converge )

Physics
2 answers:
jonny [76]3 years ago
5 0

Answer : A concave mirror is used to converge the light and a convex mirror is used to diverge the light.

Explanation :

Convex mirror : In convex mirror, the mirror is coated inside the spherical surface. It is also known as a converging mirror.

The focus lies behind the mirror.

Concave mirrors : In concave mirror, the mirror is coated outside the spherical surface. It is also known as a diverging mirror.

The focus lies infront the mirror.

As per question, a concave mirror is used to converge the light and a convex mirror is used to diverge the light.

Hence, a concave mirror is used to converge the light and a convex mirror is used to diverge the light.

Colt1911 [192]3 years ago
4 0

Answer:

converge, diverge

Explanation:

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A 200-kg boulder is 1000-m above the ground.
dem82 [27]

Answer: 1,960,000 J

Explanation:

7 0
3 years ago
The force diagram represents a girl pulling a sled with a mass of 6.0 kg to the left with a force of 10.0 N at a 30.0 degree ang
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the correct answers are 54N and -1,2m/s^2

6 0
3 years ago
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A single force acts on a 2.0 kg particle-like object in such a way that the position of the object as a function of time is give
kaheart [24]

Answer:

The work done by the force is 1435 Joule.

Explanation:

You have to apply the work-energy theorem, which associates the work and the mechanical energy

W of all non conservative forces = ΔEm = Emb - Ema

where Emb is the mechanical energy in point b and Ema is the mechanical energy in point a

Is also known that mechanical energy is the sum of potential energy and kinetic energy.

In this case, there is only kinetic energy because the potential energy is given by conservative forces like the weight but the weight is perpendicular to the displacement and because of that it doesn't produce work.

So, the work is given by:

W= Ekb - Eka, where Ek is the kinetic energy

By definition the kinetic energy is given by:

Ek=\frac{1}{2}mV^{2} where m is the mass and V is the speed.

Replacing the definition of Ek in the equation of work:

W=\frac{1}{2}mVb^{2} - \frac{1}{2}mVa^{2}

So, you have to calculate the speed in point a and in point b

You can calculate the velocity of the object as a function of time derivating the equation of the position:

V(t) = \frac{dX(t)}{dt} = \frac{d(3.0t-4.0t^{2}+1.0t^{3})  }{dt}

V(t)=3.0-8.0t+3.0t^{2}

Replacing t=0 s to obtain the speed in the initial point (point a)

Va=3.0-8(0)+3.0(0)(0)

Va=3.0 m/s

Replacing t=5.0 to obtaing the speed in final point (point b)

Vb= 3-8(5)+3(5)(5) = 38 m/s

Therefore the work is:

W = \frac{1}{2}(2.0)(38)^{2} - \frac{1}{2}(2.0)(3^{2}) =1444 - 9 = 1435 [J]

<u>Where J is Joules, the unit for work.</u>

8 0
3 years ago
A kind of variable that a researcher purposely changes in an investigation is constant. controlled. dependent. independent.
AysviL [449]
I think the correct answer would be the last option. A kind of variable that a researcher purposely changes in an investigation is the independent variable. It is the value that does not depend to any change in any variable involved. Instead, it is the one that affects the other variable called the dependent variable. The dependent variable is the variable that is being tested or studied. Also, along with these two there are variables that are held equal all through out the research. These are called the constants. These constants are factors that might affect the dependent variable that is why they are held constant to prevent more errors.
3 0
3 years ago
The knee extensors insert on the tibia at an angle of 30 degrees (from the longitudinal axis of the tibia), at a distance of 3 c
Reika [66]

Answer:

the knee extensors must exert 15.87 N

Explanation:

Given the data in the question;

mass m = 4.5 kg

radius of gyration k = 23 cm = 0.23 m

angle ∅ = 30°

∝ = 1 rad/s²

distance of 3 cm from the axis of rotation at the knee r = 3 cm = 0.03 m

using the expression;

ζ = I∝

ζ = mk²∝

we substitute

ζ = 4.5 × (0.23)² × 1

ζ  = 0.23805 N-m

so

from; ζ = rFsin∅

F = ζ / rsin∅

we substitute

F = 0.23805 / (0.03 × sin( 30 ° )

F = 0.23805 / (0.03 × 0.5)

F F = 0.23805 / 0.015

F = 15.87 N

Therefore, the knee extensors must exert 15.87 N

7 0
3 years ago
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