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STatiana [176]
4 years ago
14

HELP! Ammeters are placed on each branch of a parallel circuit. How will their readings compare?

Physics
1 answer:
anyanavicka [17]4 years ago
6 0

Answer: A. They all be the same.

Explanation: In a series circuit the current remains the same the only varible that differs is voltage.

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Which change occurs only in males during puberty
gayaneshka [121]
Enlargement of the scrotum and testes
8 0
2 years ago
A 1.5 kg rock is dropped from a height of 2.0 meters onto a spring that
Maslowich

Answer:

29.4 J

Explanation:

Before the drop, the system has only the gravitational potential energy, and this energy us given by mass×gravity×height:

1.5•9.8•2 = 29.4 J

7 0
3 years ago
8. A hiker walks 2.3 km east and then 4.1 km north. What is her displacement?
Zolol [24]
Firstly , draw the path 2.3 to east and 4.1 to the north. you’ll get a right - angle triangle . the hypotenuse is the displacement.

to find the distance , use Pythagoras theorem.

let the displacement = c

c ^ 2 = 2.3 ^ 2 + 4.1 ^ 2

c = 4.7 km

then , you need to find the angle.

tan theta = 4.1 / 2.3

theta = 61 degree

i am sorry if my answer was wrong but i hope it helps you and you can understand it : )
8 0
3 years ago
A disk, initially rotating at 146 rad/s, is slowed down with a constant angular acceleration of magnitude 4.55 rad/s2. (a) How m
GrogVix [38]

a) 32.1 s

b) 2342 rad

Explanation:

a)

To solve this problem, we can use the equivalent of the suvat equations for a rotational motion.

In fact, the motion of the disk is a rotational motion with unifom angular acceleration.

So we can use the following suvat equation:

\omega_f = \omega_i + \alpha t

where:

\omega_i is the initial angular velocity

\omega_f is the final angular velocity

\alpha is the angular acceleration

t is the time elapsed

In this problem:

\omega_i = 146 rad/s is the initial angular velocity

\omega_f=0, since the disk comes to a stop

\alpha = -4.55 rad/s^2 (negative since the disk is slowing down)

Therefore, the time taken to stop is

t=\frac{\omega_f - \omega_i}{\alpha}=\frac{0-146}{-4.55}=32.1 s

b)

To solve this part of the problem, we can use another suvat equation for the rotational motion, which is:

\theta = \omega_i t + \frac{1}{2}\alpha t^2

where

\omega_i is the initial angular velocity

\alpha is the angular acceleration

t is the time elapsed

\theta is the angular displacement covered

For the disk in this problem:

\omega_i = 146 rad/s is the initial angular velocity

\alpha = -4.55 rad/s^2 (negative since the disk is slowing down)

t = 32.1 s (time elapsed, found in part a)

Substituting, we find the angle through which the disk has rotated in this time:

\theta = (146)(32.1)+\frac{1}{2}(-4.55)(32.1)^2=2342 rad

8 0
4 years ago
Something has a mass of 40 kg and a velocity of 1 m/s
lesantik [10]
  • m=40kg
  • v=1m/s

\\ \sf\Rrightarrow K.E=\dfrac{1}{2}mv^2

\\ \sf\Rrightarrow K.E=\dfrac{1}{2}(40)(1)^2

\\ \sf\Rrightarrow K.E=20J

<h3>Part 2:-</h3>
  • m=80kg

\\ \sf\Rrightarrow K.E=\dfrac{1}{2}(80)(1)^2

\\ \sf\Rrightarrow K.E=40J

  • Yes
6 0
3 years ago
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