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lesantik [10]
3 years ago
11

Explain how you could find out whether of not an unknown liquid is water

Physics
2 answers:
qaws [65]3 years ago
7 0
 use the different characteristics of water such as freezing and boiling points, waters density, or using your five senses. Smell it, but don't taste it, feel it, listen to it. It might crackle or pop if it has carbon.
Anika [276]3 years ago
5 0
I know that density of water is 1000kg per cubic meter or 1g per 1ml
I would take beaker and scales.
1) I would measure liquid's weight (in g)
2) measure volume (in mL)
3) divide weight by measure
4) if would get 1 as result - it's water
5) if it's above or below 1 - it's not the water
 
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dusya [7]

Answer: no

Explanation:

because the object is moving downwards so it will be  called decceleration . which is the opposite of acceleration .

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3 years ago
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Help please i will mark brainlist!!
Dmitrij [34]
The answer is A.


p=m/v
p= 240/60
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A car travels at a constant velocity of 20.0 meters/second for 15 seconds. What is the power of the car if the initial force app
Zielflug [23.3K]
Work done by the force = Force x displacement. Power = work done/time = F.s/t = F.u.t/t = F.u = 95 x 20 = 1900J.                                                                                                                                                                                               {S=ut because acceleration is zero since car is moving at constant velocity}. 
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3 years ago
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Air is cooled in a process with constant pressure of 150 kPa. Before the process begins, air has a specific volume of 0.062 m^3/
Mama L [17]

Answer:

The pressure is constant, and it is P = 150kpa.

the specific volumes are:

initial = 0.062 m^3/kg

final = 0.027 m^3/kg.

Then, the specific work can be written as:

W = \int\limits^{vf}_{vi} {Pdv} \, = P(vf - vi) = 150kPa*(0.0027 - 0.062)m^3/kg = -5.25 kPa*m^3/kg.

The fact that the work is negative, means that we need to apply work to the air in order to compress it.

Now, to write it in more common units we have that:

1 kPa*m^3 = 1000J.

-5.25 kPa*m^3/kg = -5250 J/kg.

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3 years ago
an astronaut weighs 104 newtons on the moon where the strength of gravity is 1.6 newtons per kilogram what is her mass
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M = W/g
mass (m)
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