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lesantik [10]
3 years ago
11

Explain how you could find out whether of not an unknown liquid is water

Physics
2 answers:
qaws [65]3 years ago
7 0
 use the different characteristics of water such as freezing and boiling points, waters density, or using your five senses. Smell it, but don't taste it, feel it, listen to it. It might crackle or pop if it has carbon.
Anika [276]3 years ago
5 0
I know that density of water is 1000kg per cubic meter or 1g per 1ml
I would take beaker and scales.
1) I would measure liquid's weight (in g)
2) measure volume (in mL)
3) divide weight by measure
4) if would get 1 as result - it's water
5) if it's above or below 1 - it's not the water
 
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You hang a tv on your wall. What kind of energy does it have?
lara31 [8.8K]

Answer:

potential, not moving

Explanation:

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3 years ago
Q6. When a girl steps on to a weighing machine, it shows a reading of 42kg.
tigry1 [53]

Answer:

92.5 pounds

Explanation:

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2 years ago
A small electric motor produces a force of 5 N that moves a remote-control car 5 m every second. How much power does the motor p
kati45 [8]

Answer:

Explanation:

Given:

Force, f = 5 N

Velocity, v = 5 m/s

Power, p = energy/time

Energy = mass × acceleration × distance

Poer, p = force × velocity

= 5 × 5

= 25 W.

Note 1 watt = 0.00134 horsepower

But 25 watt,

0.00134 hp/1 watt × 25 watt

= 0.0335 hp.

4 0
3 years ago
Read 2 more answers
A student pushes a 0.2 kg box against a spring causing the spring to compress 0.15 m. When the spring is released, it will launc
german

Answer:

The maximum height the box will reach is 1.72 m

Explanation:

F = k·x

Where

F = Force of the spring

k = The spring constant = 300 N/m

x  = Spring compression or stretch = 0.15 m

Therefore the force, F of the spring = 300 N/m×0.15 m = 45 N

Mass of box = 0.2 kg

Work, W, done by the spring = \frac{1}{2} kx^2 and the kinetic energy gained by the box is given by KE = \frac{1}{2} mv^2

Since work done by the spring = kinetic energy gained by the box we have

\frac{1}{2} mv^2 =  \frac{1}{2} kx^2  therefore we have v = \sqrt{\frac{kx^2}{m} } = x\sqrt{\frac{k}{m} } = 0.15\sqrt{\frac{300}{0.2} } = 5.81 m/s

Therefore the maximum height is given by

v² = 2·g·h or h = \frac{v^2}{2g} = \frac{5.81^{2} }{2*9.81} = 1.72 m

6 0
3 years ago
A car turns a certain curve of radius 24.98 m with constant linear speed of
Anastaziya [24]

Answer:

3525.19 kg

Explanation:

The computation of the mass of the car is shown below:

As we know that

Fc = m × V^2 ÷ R

m = Fc × R ÷ V^2

Provided that:

Fc = 34.652 kN = 34652 N

R = Radius = 24.98 m

V = speed = 15.67 m/s

So,

m = 34652 × 24.98 ÷ 15.67^2

 = 3525.19 kg

7 0
3 years ago
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