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Alik [6]
3 years ago
9

A rectangular block of mass 30 kg measures 0.1 m by 0.4 m by 1.5 m.

Physics
2 answers:
ad-work [718]3 years ago
8 0

We have m=30\mathrm{kg} and g\approx10\mathrm{\frac{m}{s^2}}.

Calculate force (weight) by using F=mg.

F=mg=30\mathrm{kg}\cdot10\mathrm{\frac{m}{s^2}}=300\mathrm{N}

Hope this helps.

Oksanka [162]3 years ago
4 0

Answer:

294.30N

Explanation:

We use the following relationship to calculate the weight W of the block;

W=mg............(1)

where m is its mass and g is acceleration due to gravity. The value of g is taken as 9.81m/s^2, the mass of the object is given by m = 30kg. Hence;

W=30*9.81\\W=294.3N

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The slope of a graph of position vs time

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A 126- kg astronaut (including space suit) acquires a speed of 2.70 m/s by pushing off with her legs from a 1800-kg space capsul
jeka94

The change in the speed of the space capsule will be -0.189 m/s.

The average force exerted by each on the other will be 567 N.

The kinetic energy of each after the push for the astronaut and the capsule are 459.27 J and 32.14 J.

<h3>Given:</h3>

Mass of the astronaut, m_a = 126 kg

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Mass of the space capsule, m_{c} = 1800kg

The initial momentum of the astronaut-capsule system is zero due to rest.

P_f = m_av_a + m_cv_c

P_I = 0

m_av_a + m_cv_c = 0

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   = \frac{126* 2.70}{1800}

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Therefore,

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FΔt = ΔP

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t is time interval = 0.600s

F = ΔP/Δt

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Therefore, the average force exerted by each on the other will be 567 N.

The Kinetic Energy of the astronaut;

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K.E = \frac{1}{2} m v^2

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Therefore, the kinetic energy of each after the push for the astronaut and the capsule are 459.27 J and 32.14 J.

Learn more about kinetic energy here:

brainly.com/question/26520543

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