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Alik [6]
3 years ago
9

A rectangular block of mass 30 kg measures 0.1 m by 0.4 m by 1.5 m.

Physics
2 answers:
ad-work [718]3 years ago
8 0

We have m=30\mathrm{kg} and g\approx10\mathrm{\frac{m}{s^2}}.

Calculate force (weight) by using F=mg.

F=mg=30\mathrm{kg}\cdot10\mathrm{\frac{m}{s^2}}=300\mathrm{N}

Hope this helps.

Oksanka [162]3 years ago
4 0

Answer:

294.30N

Explanation:

We use the following relationship to calculate the weight W of the block;

W=mg............(1)

where m is its mass and g is acceleration due to gravity. The value of g is taken as 9.81m/s^2, the mass of the object is given by m = 30kg. Hence;

W=30*9.81\\W=294.3N

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7) Three resistors having resistances of 4.0 Ω, 6.0 Ω, and 10.0 Ω are connected in parallel. If the combination is connected in
viva [34]

Answer:

A, 0.59A

Explanation:

The total resistance in the circuit is the resistances in parallel plus that in series.

Total resistance for those in parallel is;

1/(1/4 +1/6 +1/10) = 1/ (15+10+6 /60)

1/(31/60)= 60/31 ohms

Hence total resistance of the circuit is;

60/31 + 2 = (60+62)/31 = 122/31=3.94 ohms

To calculate the current flowing through the 10ohm resistance we need to know the voltage drop by subtracting the voltage drop in the 2ohm resistance from the total voltage drop.

Voltage drop on the 2 ohm resistance is;

Current on the 2 ohm resistor × 2 ohms

V = I ×R ; I - current

R - resistance

Current drop on the 2ohm resistance is;

Total voltage in the circuit/ total resistance in the circuit

12/3.94= 3.05A

Voltage drop on the 2 ohm resistance;

3.05 × 2 = 6.10volts

Hence voltage drop on the parallel resistance would be ;

12-6.10= 5.90V

Now voltage drop in a parallel circuit is the same hence 5.90v is dropped in each of the parallel resistance.

That said, the current drop on the 10 ohm resistor would be;

5.90/10 = 0.59A

Remember V= I× R so that I = V/R

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3 years ago
A child looks at his reflection in a spherical Christmas tree ornament 8.0 cm in diameter in season that the image of his face i
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radius = diameter/2 = 8/2

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focal length, f = radius of curvature/2 = 4/2

f = 2

Recall,

magnification = image d

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1 year ago
What are three ways that you know an object has accelerated
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An object has undergone acceleration if ...

-- it's moving faster than it was before
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or
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3 years ago
A delivery truck travels with a constant velocity up an 8 slope. A 60 kg box sits on the floor of the truck and, because of sta
Blababa [14]

Explanation:

Given that,

The slope of the ramp, \theta=8^{\circ}

Mass of the box, m = 60 kg

(a) Distance covered by the truck up the slope, d = 300 m

Initially the truck moves with a constant velocity. We know that the net work done on the box is equal to 0 as per work energy theorem as :

W=\dfrac{1}{2}m(v^2-u^2)=0

u and v are the initial and the final velocity of the truck

(b) The work done on the box by the force of gravity is given by :

W=Fd\ cos\theta

Here, \theta=90+8=98^{\circ}

W=mgd\ cos\theta

W=60\times 9.8\times 300\ cos(98)

W = -24550.13 J

(c) What is the work done on the box by the normal force is equal to 0 as the angle between the force and the displacement is 90 degrees.

(d) The work done by friction is given by :

W_f=-W

W_f=24550.13\ J

Hence, this is the required solution.

6 0
3 years ago
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