Answer:
Elements that fall between those on the left and right sides of the periodic table
Explanation:
Transition metals:
These are present at the center of periodic table.
These are d-block elements.
They include the elements of group 3 to 12 in periodic table.
They have large charge to radius ratio.
They mostly form paramagnetic compounds.
They shoes more than one oxidation state.
They form colored compounds.
They all have high melting and boiling point.
They have high densities.
They form stable complexes.
The elements of f-block are also transition but they are called inner transition.These are consist of two series lanthanide and actinides.
we have
work done (W)= force(F) × displacemen(s)
or, 80= F× 8
or, F= 10 N
therefore, 10 N force is required to lift the rock.
A because the outcome of this reaction exists a radical formed by the oxidation of an aromatic amine's or phenol's ring substituent. The hydroxyl group of a phenol serves as the ring substituent in this condition.
<h3>Which two enzyme types are required for the two-step process of converting cytosine to 5 hmC?</h3>
- The methyl group exists moved to cytosine in the first step, and it exists then hydroxylated in the second stage.
- Thus, a transferase and an oxidoreductase exist as the two groups of enzymes needed.
<h3>Which kind of interaction between proteins and the dextran column material is most likely to take place?</h3>
- Hydrogen bonding because the glucose's OH would create an H-bond with any disclosed polar side chains on a protein surface.
<h3>Two out of the four proteins would adhere to a cation-exchange column at what buffer pH?</h3>
- Only positively charged proteins can attach to a cation-exchange column, and this can only occur when the pH exists lower than the pI.
- Proteins A and B would both be positively charged at pH 7.0.
To learn more about hydroxyquinoline refer to:
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Missing question:
<span>(1) C2H5OH (3) C12H22O11
(2) C6H12O6 (4) CH3COOH.
Answer is: 4) CH</span>₃COOH, acetic acid.
In water, acetic acid dissociates on ions, so it can conduct electricity:
CH₃COOH(aq) ⇄ CH₃COO⁻(aq) + H⁺(aq).
When we put
electrodes (cathode and anode) in acetic acid solution, positive and negative
ions migrate to electrodes.<span>
Negative acetate ions go to positive electrode
and gives electrons to electrode.
<span>Positive hydrogen ions go to negative electrode
and gain electrons.</span></span>
