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lisov135 [29]
2 years ago
6

Pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Mathematics
2 answers:
Anna [14]2 years ago
8 0

Answer:

180(n-2)

Step-by-step explanation:

that's to find interior angles

VashaNatasha [74]2 years ago
3 0

Answer:

180(n-2) is formula for finding interior angles if n is number of sides.

Step-by-step explanation:

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Jason has two bags with 6 tiles each.
dimaraw [331]

Answer:

1/4.

Step-by-step explanation:

I am assuming that there are 3 even and 3 odd tiles in each bag.

Probability( drawing an even tile form one bag) = 3/6 = 1/2.

The probability  of drawing  an even from the first and an even from the second = 1/2 * 1/2 = 1/4 (answer).

The individual probabilities  are multiplied because the 2 events are independent.

8 0
3 years ago
Read 2 more answers
The revenue from selling xshirts is r(x) 15x The cost of buying x shirts is c(x) 7x + 20. The profit from selling xshirts is px)
timurjin [86]

The profit would be the difference between the total amount earned after selling each and every shirt and the costs of buying them so

p(x)= r(x)- c(x)

7x-20?

5 0
3 years ago
Read 2 more answers
Show the tens fact you used. Write the difference.
Mars2501 [29]
What exactly do you mean? Is there answer's to the problem or more to the problem?
7 0
3 years ago
Help please and thank you
aksik [14]
Remember
(a^b)^c=a^{bc}
and
\frac{x^a}{x^b}=x^{a-b}


so

\frac{(7^2)^5}{7^{-6}}=
\frac{7^{2*5}}{7^{-6}}=
\frac{7^{10}}{7^{-6}}=
7^{10-(-6)}=
7^{10+6}=
7^{16}

the answer is D
5 0
3 years ago
Please consider the following values for the variables X and Y. Treat each row as a pair of scores for the variables X and Y (wi
Studentka2010 [4]

Answer:

The Pearson's coefficient of correlation between the is 0.700.

Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables <em>X</em> and <em>Y</em> is:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

The formula to compute covariance is:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

The formula to compute the variances are:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}

Consider the table attached below.

Compute the covariance as follows:

Cov(X, Y)=n\cdot \sum XY-\sum X \cdot\sum Y

                 =(5\times 165)-(30\times 25)\\=75

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50

Compute the correlation coefficient as follows:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

            =\frac{75}{\sqrt{230\times 50}}

            =0.69937\\\approx0.70

Thus, the Pearson's coefficient of correlation between the is 0.700.

5 0
3 years ago
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