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igomit [66]
3 years ago
13

The conversion of 1 mole of water at 0°c to 1 mole of ice at 0°c releases 6.01 kj. what must be true about the heat absorbed dur

ing the melting of 1 mole of ice at 0°c to 1 mole of water at 0°c? it must be less than 6.01 kj. it must be greater than 6.01 kj. it must be 6.01 kj.
Chemistry
2 answers:
Stels [109]3 years ago
7 0

Answer: it must be 6.01 kJ.

Explanation:

Latent heat of freezing is the amount of heat released to convert 1 mole of liquid to 1 mole of solid at atmospheric pressure.

H_2O(l)\rightarrow H_2O(s)

Given: latent heat of freezing is 6.01 kJ.

Latent heat of fusion is the amount of heat required to convert 1 mole of solid to 1 mole of liquid at atmospheric pressure. If latent heat of freezing is 6.01 kJ, latent heat of fusion will be same but the heat will be absorbed.

H_2O(s)\rightarrow H_2O(l)

love history [14]3 years ago
6 0
It must be 6.01 kj
................



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Answer:

The answer to your question is 4

Explanation:

Chemical reaction

                C₂H₆  +  O₂  ⇒  CO₂  +  H₂O

           Reactants    Elements    Products

                  2            Carbon              1

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Balanced chemical reaction

                2C₂H₆  +  7O₂  ⇒  4CO₂  +  6H₂O

           Reactants    Elements    Products

                  4            Carbon             4

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3 years ago
A student is trying to develop a model of an instant heat pack. What is the essential characteristic of the chemical reaction th
Lana71 [14]

The standard enthalpy of reaction should be negative.

<h3>What is enthalpy?</h3>

A thermodynamic quantity equivalent to the total heat content of a system. It is equal to the internal energy of the system plus the product of pressure and volume.

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Hence, option B is correct.

Learn more about enthalpy here:

brainly.com/question/13775366

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Answer:

             1.37 × 10²³ Atoms of Mercury  

Solution:

Step 1: Calculate Mass of Mercury using following formula,

                               Density  =  Mass ÷ Volume

Solving for Mass,

                               Mass  =  Density × Volume

Putting values,

                               Mass  =  13.55 g.cm⁻³ × 3.4 cm³                ∴ 1 cm³ = 1 cc

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Step 2: Calculating number of Moles using following formula;

                               Moles  =  Mass ÷ M.mass

Putting values,

                               Moles  =  46.07 g ÷ 200.59 g.mol⁻¹

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Step 3: Calculating Number of Atoms using following formula;

                               Number of atoms  =  Moles × 6.022 ×10²³

Putting value of moles,

                               Number of Atoms  =  0.229 mol × 6.022 × 10²³

                              Number of Atoms  =  1.37 × 10²³ Atoms of Hg

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