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3 years ago

What is the molarity of a solution if 5 moles of solute are dissolved in 8 L of solvent.

Chemistry

1 answer:

tankabanditka [31]3 years ago

6 0

Answer:

0.625mol/L

Explanation:

Given parameters:

Number of moles of solute = 5moles

Volume of solvent = 8L

Unknown:

Molarity = ?

Solution:

Molarity is the number of moles of solute per unit volume of solution. It is mathematically expressed as

Molarity = $\frac{number of moles }{Volume}$

Molarity = $\frac{5}{8}$ = 0.625mol/L

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Ketones undergo a reduction when treated with sodium borohydride, NaBH4. The product of the above reaction has the following spe

Anna71 [15]

Answer:

The product is cyclohexanol

Explanation:

Firstly,

A ketone undergo a borohydride reduction reaction to form an alcohol as below,

R-CO-R' ⇒ R-CO(OH)-R'

IR Spectrum confirms that alcohol group is existed with the peak at 3400 cm⁻¹
From 1H-NMR, the product has 10 hydrogen atoms, the MS suggest that the formula is C₅H₁₀O (M = 86). With this formula, the alcohol is monosaturated. Since, the substance already underwent reduction reaction, the only way to suggest a monosaturated compound is a cyclic alcohol. So the compound is cyclopentanol.
Check with other spectroscopic properties,

3 signals of 13C NMR confirms the structure is symmetrical, δ 24.2, (-CH₂-CH₂-CH(CH₂-)-OH), δ 35.5 (-CH₂-CH₂-CH(CH₂-)-OH), δ 73.3 (-CH₂-CH₂-CH(CH₂-)-OH).

1H NMR confirms,

1.56 δ (4H, triplet) - (-CH₂-CH₂-CH-OH) ; triplet as coupling with 2 H,

1.78 δ (4H, multiplet) - (-CH₂-CH₂-CH-OH); multiplet as coupling with 2H of CH₂, 1 H of CH

3.24 δ (1H, quintet); - (-CH₂-CH₂-CH(CH₂-)-OH), coupling with4 H of 2 group of CH₂

3.58 δ (1H, singlet); - (-CH₂-CH₂-CH(CH₂-)-OH), hydrogen of alcohol group, not tend to coupling with other hydrogen

4 0

3 years ago

you are given 500 mL of a 5M stock solution of ammonium chloride but for your experiment, you only need 100 mL of a 0.65M soluti

mafiozo [28]

Answer:

13ml

Explanation:

to prepare dis solution first you need a volumetric flask of 100ml calibrated .
using dilution formulae u will need 13ml from the stock
measure 13ml of the 5M stock of the 500ml
then drop it into the 100ml calibrated flask
then add water till it reach d mark and you shake thoroughly

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3 years ago

An electron can be added to halogen atom to force a halide ion with

Lilit [14]

An electron can be added to halogen atom to force a halide ion with 8 valence electrons

An atom can be defined as the smallest part of an element which can take part in a chemical reaction.

However whenever, an electron is added to halogen atom to force a halide ion with 8 different valence electrons

So therefore; an electron can be added to halogen atom to force a halide ion with 8 valence electrons

Learn more about halogens:

brainly.com/question/18276987

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2 years ago

Which part of a feedback mechanism causes change to make up for the departure from the set point? A. sensor B. effector C. respo

koban [17]

I would have to say C. Response.

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3 years ago

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Ammonia, nh3, is a weak base with a kb = 1.8 x 10-5. in a 0.8m solution of ammonia, which has a higher concentration: ammonia (n

insens350 [35]

Answer is: concentration ammonia is higher than concentration of ammonium ion.
Chemical reaction of ammonia in water: NH₃ + H₂O → NH₄⁺ + OH⁻.
Kb(NH₃) = 1,8·10⁻⁵.
c₀(NH₃) = 0,8 mol/L.
c(NH₄⁺) = c(OH⁻) = x.
c(NH₃) = 0,8 mol/L - x.
Kb = c(NH₄⁺) · c(OH⁻) / c(NH₃).
0,000018 = x² / 0,8 mol/L - x.
solve quadratic equation: x = c(NH₄⁺) = 3,79·10⁻³ mol/L.

7 0

3 years ago