In a laboratory investigation, an HCl(aq) solution with a pH value of 2 is used to determine the molarity of a KOH(aq) solution.
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Answer : The excess reactant is,
The leftover amount of excess reagent is, 7.2 grams.
Solution : Given,
Mass of = 105.0 g
Mass of = 78.0 g
Molar mass of = 80.11 g/mole
Molar mass of = 18 g/mole
Molar mass of = 100.09 g/mole
First we have to calculate the moles of and
.
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 1 mole of react with 3 mole of
So, 1.31 moles of react with
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Left moles of excess reactant = 4.33 - 3.93 = 0.4 moles
Now we have to calculate the mass of excess reactant.
Thus, the leftover amount of excess reagent is, 7.2 grams.