For every 2 Mol NaOH you would get 1 Mol N2H4
Answer:
The molar mass of the unknown gas is ![\mathbf{ 51.865 \ g/mol}](https://tex.z-dn.net/?f=%5Cmathbf%7B%2051.865%20%5C%20%20g%2Fmol%7D)
Explanation:
Let assume that the gas is O2 gas
O2 gas is to effuse through a porous barrier in time t₁ = 4.98 minutes.
Under the same conditions;
the same number of moles of an unknown gas requires time t₂ = 6.34 minutes to effuse through the same barrier.
From Graham's Law of Diffusion;
Graham's Law of Diffusion states that, at a constant temperature and pressure; the rate of diffusion of a gas is inversely proportional to the square root of its density.
i.e
![R \ \alpha \ \dfrac{1}{\sqrt{d}}](https://tex.z-dn.net/?f=R%20%5C%20%20%5Calpha%20%20%5C%20%5Cdfrac%7B1%7D%7B%5Csqrt%7Bd%7D%7D)
where K = constant
If we compare the rate o diffusion of two gases;
![\dfrac{R_1}{R_2}= {\sqrt{\dfrac{d_2}{d_1}}](https://tex.z-dn.net/?f=%5Cdfrac%7BR_1%7D%7BR_2%7D%3D%20%7B%5Csqrt%7B%5Cdfrac%7Bd_2%7D%7Bd_1%7D%7D)
Since the density of a gas d is proportional to its relative molecular mass M. Then;
![\dfrac{R_1}{R_2}= {\sqrt{\dfrac{M_2}{M_1}}](https://tex.z-dn.net/?f=%5Cdfrac%7BR_1%7D%7BR_2%7D%3D%20%7B%5Csqrt%7B%5Cdfrac%7BM_2%7D%7BM_1%7D%7D)
Rate is the reciprocal of time ; i.e
![R = \dfrac{1}{t}](https://tex.z-dn.net/?f=R%20%3D%20%5Cdfrac%7B1%7D%7Bt%7D)
Thus; replacing the value of R into the above previous equation;we have:
![\dfrac{R_1}{R_2}={\dfrac{t_2}{t_1}}](https://tex.z-dn.net/?f=%5Cdfrac%7BR_1%7D%7BR_2%7D%3D%7B%5Cdfrac%7Bt_2%7D%7Bt_1%7D%7D)
We can equally say:
![{\dfrac{t_2}{t_1}}= {\sqrt{\dfrac{M_2}{M_1}}](https://tex.z-dn.net/?f=%7B%5Cdfrac%7Bt_2%7D%7Bt_1%7D%7D%3D%20%20%7B%5Csqrt%7B%5Cdfrac%7BM_2%7D%7BM_1%7D%7D)
![{\dfrac{6.34}{4.98}}= {\sqrt{\dfrac{M_2}{32}}](https://tex.z-dn.net/?f=%7B%5Cdfrac%7B6.34%7D%7B4.98%7D%7D%3D%20%20%7B%5Csqrt%7B%5Cdfrac%7BM_2%7D%7B32%7D%7D)
![M_2 = 32 \times ( \dfrac{6.34}{4.98})^2](https://tex.z-dn.net/?f=M_2%20%3D%2032%20%5Ctimes%20%28%20%5Cdfrac%7B6.34%7D%7B4.98%7D%29%5E2)
![M_2 = 32 \times ( 1.273092369)^2](https://tex.z-dn.net/?f=M_2%20%3D%2032%20%5Ctimes%20%28%201.273092369%29%5E2)
![M_2 = 32 \times 1.62076418](https://tex.z-dn.net/?f=M_2%20%3D%2032%20%5Ctimes%201.62076418)
![\mathbf{M_2 = 51.865 \ g/mol}](https://tex.z-dn.net/?f=%5Cmathbf%7BM_2%20%3D%2051.865%20%5C%20%20g%2Fmol%7D)
Answer:
See explaination
Explanation:
Chiral carbons are carbons that have four different groups, so C atoms 1, 4, and 5 are chiral carbons and thus H atoms are shown for those atoms.