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KatRina [158]
3 years ago
14

Sunspots sit on the sun’s

Chemistry
1 answer:
Crank3 years ago
7 0

The answer is Photosphere Apex.      

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How many grams of sulfur are required in the preparation of 35.7 moles of sulfur dioxide Sg + O2 SO2​
lidiya [134]
  • S+O_2-->SO_2

Its balanced already

So

  • 1 mol SO_2 require 1 mole sulphur
  • 35.7moles require 35.7mol sulphur

Mass of S

  • 35.7(32)
  • 1142.4g
6 0
2 years ago
How many dimes could you trade for 360 pesos? $1 = 1500 pesos.
sveta [45]

Answer:

The correct option is (d).

Explanation:

It is given that,

1$ = 1500 pesos

We need to convert 360 pesos into dimes

We can convert 360 pesos to dollars as follows:

360\ \text{pesos}=\$\dfrac{1}{1500}\times 360\\\\=$0.24

360 pesos is equal to $0.24

Also, 1 dollar = 10 dimes

We can covert 0.24 dollar to dimes as follows :

0.24 dollar = 10 × 0.24 dimes

0.24 dollar = 2.4 dimes

or

360 pesos = 2.4 dimes

7 0
3 years ago
In acid solution, water can add to the double bond of 2-butenedioic acid to form 2-hydroxysuccinic acid.
satela [25.4K]
So, what is the question?
6 0
3 years ago
The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: E = R_y/n^2 In this equation R_y stands
Katarina [22]

Answer:

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is 5.23\times 10^{-5} m

Explanation:

Given :

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula:

E=\frac{R_y}{n^2}

R_y=2.18\times 10^{-18} J =  Rydberg energy

n =  principal quantum number of the orbital

Energy of 11th orbit = E_{11}

E_{11}=\frac{2.18\times 10^{-18} J}{11^2}=1.80\times 10^{-20} J

Energy of 10th orbit = E_{10}

E_{10}=\frac{2.18\times 10^{-18} J}{10^2}=2.18\times 10^{-20} J

Energy difference between both the levels will corresponds to the energy of the wavelength of the line which can be calculated by using Planck's equation.

E'=E_{10}-E_{11}=2.18\times 10^{-20} J-1.80\times 10^{-20} J

=E'=0.38\times 10^{-20} J

\lambda =\frac{hc}{E'} (Planck's' equation)

\lambda = \frac{6.626\times 10^{-34} Js\times 3\times 10^8 m/s}{0.38\times 10^{-20} J}

\lambda = 5.2310\times 10^{-5} m\approx 5.23\times 10^{-5} m

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is 5.23\times 10^{-5} m

3 0
3 years ago
Equal amounts of methylene blue (319.85 g/mol) and potassium permanganate (158.034 g/mol) dyes were added to identical agar plat
tamaranim1 [39]

Answer:

Potassium permanganate.

Explanation:

Both substances are dyes, but the methylene blue has a bigger molecular mass (319.85 g/mol), that means that the particles are bigger in comparison with the potassium permanganate that has a molecular mass of 158.034 g/mol.

Since the molar mass is the half in the case of potassium permanganate, it can be considered that the particle size is the half in size. In the agar, a smaller particle will present less resistance to flow, that means that it going to move faster.

4 0
3 years ago
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