Answer:
![\Delta V = \frac{q ln(\frac{b}{a})}{2\pi \epsilon_0 L}](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%20%5Cfrac%7Bq%20ln%28%5Cfrac%7Bb%7D%7Ba%7D%29%7D%7B2%5Cpi%20%5Cepsilon_0%20L%7D)
Explanation:
As we know that the charge per unit length of the long cylinder is given as
![\lambda = \frac{q}{L}](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7Bq%7D%7BL%7D)
here we know that the electric field between two cylinders is given by
![E = \frac{2k\lambda}{r}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B2k%5Clambda%7D%7Br%7D)
now we know that electric potential and electric field is related to each other as
![\Delta V = - \int E.dr](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%20-%20%5Cint%20E.dr)
![\Delta V = -\int_a^b (\frac{2k\lambda}{r})dr](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%20-%5Cint_a%5Eb%20%28%5Cfrac%7B2k%5Clambda%7D%7Br%7D%29dr%20)
![\Delta V = -2k \lambda ln(\frac{b}{a})](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%20-2k%20%5Clambda%20ln%28%5Cfrac%7Bb%7D%7Ba%7D%29)
![\Delta V = \frac{\lambda ln(\frac{b}{a})}{2\pi \epsilon_0}](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%20%5Cfrac%7B%5Clambda%20ln%28%5Cfrac%7Bb%7D%7Ba%7D%29%7D%7B2%5Cpi%20%5Cepsilon_0%7D)
![\Delta V = \frac{q ln(\frac{b}{a})}{2\pi \epsilon_0 L}](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%20%5Cfrac%7Bq%20ln%28%5Cfrac%7Bb%7D%7Ba%7D%29%7D%7B2%5Cpi%20%5Cepsilon_0%20L%7D)
Answer:
The correct option is;
The graduate cylinder with more water has more thermal energy because it is holding more water molecules
Explanation:
Given that the thermal energy of the system is the energy possessed by the system by virtue of the increased motion of the particles by virtue of a transfer of heat, when the content of the system is heated
The thermal energy, Q is given by the following equation;
Q = Mass, m × The specific heat capacity, C × The change in temperature, ΔT
Given that the graduated cylinder with more water has more mass and therefore, more water molecules, than the cylinder with less water, the cylinder with more water has more thermal energy.
3 as a single number is considered a sf
I think the correct answer from the choices would be that metals donate electrons to nonmetals. Ionic bonding involves transfer of valence electrons. The metal looses its valence electrons which makes it a cation while the nonmetal accepts these electrons.
Answer:
v=0.60 m/s
Explanation:
Given that
m ₁= 390 kg ,u ₁= 0.5 m/s
m₂ = 250 kg ,u₂ = 0.76 m/s
As we know that if there is no any external force on the system the total linear momentum of the system will be conserve.
Pi = Pf
m ₁u ₁+m₂u₂ = (m₂ + m ₁ ) v
Now putting the values in the above equation
390 x 0.5 + 250 x 0.76 = (390 + 250 ) v
![v=\dfrac{390\times 0.5+250\times 0.76}{390+250}\ m/s](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7B390%5Ctimes%200.5%2B250%5Ctimes%200.76%7D%7B390%2B250%7D%5C%20m%2Fs)
v=0.60 m/s
Therefore the velocity of the system will be 0.6 m/s.