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Zanzabum
3 years ago
11

A piston above liquid in a closed container has an area of 1m2. The piston carries a load of 350 kg. What will be the external p

ressure on the upper surface of the liquid in KPA
Physics
2 answers:
grandymaker [24]3 years ago
5 0
<span>Pressure = force / area</span>

I assume that 350kg is the mass 
Therefore, 

350 x 9.8 (gravity) = 3430N

3430 / 1 = 3430Pa

3.43 KPa


ollegr [7]3 years ago
3 0

Answer:

3.43 kPa

Explanation:

Pressure is defined as the ratio between the force applied and the area of the surface on which the force is applied:

p=\frac{F}{A}

in this problem, the force corresponds to the weight of the load, which is given by the product between its mass (350 kg) and the acceleration due to gravity (9.8 m/s^2):

F=mg=(350 kg)(9.8 m/s^2)=3430 N

And since the area on which this force is applied is A=1 m^2, the pressure exerted on the upper surface of the liquid is

p=\frac{F}{A}=\frac{3430 N}{1 m^2}=3430 Pa = 3.43 kPa

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