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valkas [14]
4 years ago
5

A current of 3.6-A flows through a conductor. Calculate how much charge passed through and cross-section of the conductor in 25s

ec.
Physics
1 answer:
Anastaziya [24]4 years ago
6 0

Answer:

90 C

Explanation:

Electric current: This can be defined as the rate of flow of electric charge in a circuit. This can be expressed mathematically as,

I = dQ/dt

dQ = Idt

∫dQ = ∫Idt

Q = It................................ Equation 1

Where Q = amount of charge, I = current, t = time.

Given: I = 3.6 A, t = 25 s.

Substituting into equation 1,

Q = 3.6(25)

Q = 90 C.

Hence the amount of charge passing through the cross section of the conductor = 90 C

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Two objects have charges 2.0 C and 1.0 C. If the objects are placed 2 meters apart, what is the magnitude of the force that the
kondor19780726 [428]

Answer:

4.5\cdot 10^9 N

Explanation:

The electric force between two charged objects is given by:

F=k\frac{q_1 q_2}{r^2}

where:

k is the Coulomb's constant

q1 and q2 are the charges of the two objects

r is their separation

In this problem:

q1 = 2.0 C

q2 = 1.0 C

r = 2 m

So, the electric force is

F=(9\cdot 10^9 Nm^2C^{-2})\frac{(2.0 C)(1.0 C)}{(2 m)^2}=4.5\cdot 10^9 N

4 0
4 years ago
Maverick and goose are flying a training mission in their F-14. They are flying at an altitude of 1500 m and are traveling at 68
lions [1.4K]

Answer:

The bomb will remain in air for <u>17.5 s</u> before hitting the ground.

Explanation:

Given:

Initial vertical height is, y_0=1500\ m

Initial horizontal velocity is, u_x=688\ m/s

Initial vertical velocity is, u_y=0(\textrm{Horizontal velocity only initially)}

Let the time taken by the bomb to reach the ground be 't'.

So, consider the equation of motion of the bomb in the vertical direction.

The displacement of the bomb vertically is S=y-y_0=0-1500=-1500\ m

Acceleration in the vertical direction is due to gravity, g=-9.8\ m/s^2

Therefore, the displacement of the bomb is given as:

S=u_yt+\frac{1}{2}gt^2\\-1500=0-\frac{1}{2}(9.8)(t^2)\\1500=4.9t^2\\t^2=\frac{1500}{4.9}\\t=\sqrt{\frac{1500}{4.9}}=17.5\ s

So, the bomb will remain in air for 17.5 s before hitting the ground.

5 0
3 years ago
Find<br>the equevalent unit<br>for Ohm using<br>the<br>geren<br>formula.<br>늘​
Brut [27]

Answer:

V/A

Explanation:

Resistance equals voltage divided by current. You already know resistance's unit is the Ohm. Voltage's unit is the Volt and current's is ths Ampere. Now you can do something like this:

1Ω=\frac{1V}{1A} ⇔

Ω=V/A

Hope this helped :)

7 0
3 years ago
The weight of an object is the product of its mass, m, and the acceleration of gravity, g (where g=9.8 m/s2). If an
Leno4ka [110]
m-mass
w-weight
g-gravitational\ acceleration

w=m*g

w=10kg*9.8m/s^2

w=98\frac{kg*m}{s^2}

You need to remember that 1\frac{kg*m}{s^2}=1N

So final answer is w=98\frac{kg*m}{s^2}=98N
4 0
3 years ago
An electron in the Bohr model of hydrogen revolves around the nucleus to:
RoseWind [281]

An electron in the Bohr model of hydrogen revolves around the nucleus to possess energy.

Answer: Option B

<u>Explanation:</u>

According to Rutherford, it was stated that electrons are the subatomic particles which revolve around the nucleus. But the error of spiral collapse of these electrons is due to absence of electrons in discrete levels. Hence, in Bohr atom model, the atom's negative or electrons are said to rotate in respective energy levels.

So, they keep on revolving around a nucleus in Bohr atom is said to revolve around a nucleus in order to possess energy. Thus, each level will exhibit discrete energy levels which will contain electrons of specific energy only.

5 0
3 years ago
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