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valkas [14]
3 years ago
5

A current of 3.6-A flows through a conductor. Calculate how much charge passed through and cross-section of the conductor in 25s

ec.
Physics
1 answer:
Anastaziya [24]3 years ago
6 0

Answer:

90 C

Explanation:

Electric current: This can be defined as the rate of flow of electric charge in a circuit. This can be expressed mathematically as,

I = dQ/dt

dQ = Idt

∫dQ = ∫Idt

Q = It................................ Equation 1

Where Q = amount of charge, I = current, t = time.

Given: I = 3.6 A, t = 25 s.

Substituting into equation 1,

Q = 3.6(25)

Q = 90 C.

Hence the amount of charge passing through the cross section of the conductor = 90 C

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Explain in your own words the interaction between the electric and magnetic fields that make up a light wave.
iVinArrow [24]

Answer:

They oscillates perpendicularly to one another, the oscillation of one field generates the other field.

Explanation:

In a light wave, an oscillating electric field of a light wave produces a magnetic field, and the magnetic field also oscillates to produce an electric field. The magnetic field and the electric field of a light wave both oscillates perpendicularly to one another. The resultant energy and direction of the wave generated as a result of these oscillating fields is propagated perpendicularly to both fields.

8 0
3 years ago
Two different simple harmonic oscillators have the same natural frequency (f=8.80 Hz) when they are on the surface of the Earth.
bekas [8.4K]

Answer:

8.80 Hz

Explanation:

The frequency of a loaded spring is given by

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

where k and m are the spring constant and the mass of the load respectively. The values of these do not change because they are internal properties of the components of the system.

Hence, the frequency of the vertical spring mass does not change and is 8.80 Hz.

On the other hand, the frequency of the simple pendulum is affected because it is given by

\dfrac{1}{2\pi}\sqrt{\dfrac{g}{l}}

where g and l are acceleration due to gravity and length of the pendulum, respectively. It is thus seen that it depends on g, which changes with location. In fact, the new frequency is given by

f_2 = 8.80\sqrt{\dfrac{1.67}{9.81}}=3.63 \text{ Hz}

3 0
3 years ago
David is driving a steady 30.0 m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady
SpyIntel [72]

Answer:

Explanation:

Let after time t , Tina catches up David .

Distance travelled by them are equal ,

Distance travelled by Tina

s = ut + 1/2 a t²

= .5 x 2.10 t²

= 1.05 t²

Distance travelled by David

= 30 t ( because of uniform velocity )

1.05 t² = 30t

t = 28.57 s

Distance travelled by Tina

= 1/2 a t²

= .5 x 2.10 x 28.57²

= 857 m approx.

7 0
2 years ago
Read 2 more answers
The thermal energy of what system does change
Inessa05 [86]

Answer:

there is the increase the temperature of cold body and decrease the temperature of hot body

4 0
2 years ago
How far apart would you have to place the poles of a 1. 5 v battery to achieve the same electric field?
Zarrin [17]

To place the poles of a 1. 5 v battery to achieve the same electric field is 1.5×10−2 m

The potential difference is related to the electric field by:

∆V=Ed

where,

∆V is the potential difference

E is the electric field

d is the distance

what is potential difference?

The difference in potential between two points that represents the work involved or the energy released in the transfer of a unit quantity of electricity from one point to the other.

We want to know the distance the detectors have to be placed in order to achieve an electric field of

E=1v/cm=100v/cm

when connected to a battery with potential difference

∆v=1.5v

Solving the equation,we find

d =  \frac{ \:Δv}{e}

=  \frac{1.5v}{100v/m}

= 1.5 \times 10 {}^{ - 2} m

learn more about potential difference from here: brainly.com/question/28166044

#SPJ4

6 0
11 months ago
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