It's important to know that diffraction gratings can be identified by the number of lines they have per centimeter. Often, more lines per centimeter is more useful because the images separation is greater when this happens. That is, the distance between lines increases.
<h2>Therefore, the answer is 2.</h2>
Answer:
c
Explanation:
Hello!
To solve this problem we need to know the velocity and position of the train as a fucntion of time and acceleration. Since the train started from rest, these are the formulas:
v = at
x = (1/2)a*t^2
From the first equation we can know the time as a division between the velocity and the acceleration:
t = (v/a)
Replacing this value in the second equation we get:
x = (1/2)*a*(v/a)^2 = v^2/(2*a)
Solving for a:
a = (1/2)*(v^2/x)
Now, we know that when x=5.6km =5600 m, the velocity of the train is v =42 m/s
Therefore:
a = (1/2)*(42^2/5600) m/s^2 = 0.1575 m/s^2
So, the answer is c, the acceleration of the train during the first 5.6 km is colse to 0.16m/S^2
C play all the songs on shuffle. entropy has to do with randomness
Raising the hook, or load by exactly 1 meter, will allow the length of the compressed material regain its original length, provided it wasn't deformed by the 5% compression.
<h3>Hooke's law </h3>
Hooke's law states that the force applied to an elastic material is directly proportional to the extension of the material provided that the elastic limit of the material is not exceeded.
When the length of the material is compressed by 5%, the material will regain its original size and shape when the applied load is removed, if the material was not deformed by the compression.
Thus, raising the hook, or load by exactly 1 meter, will allow the length of the compressed material regain its original length, provided it wasn't deformed by the 5% compression.
Learn more about Hooke's law here: brainly.com/question/2648431
<span>the rocket's mass decreases as its fuel is consumed. the same net force acting on a smaller mass results in a larger acceleration</span>