Question

A 0.5kg baseball experiences a 10n force for a duration of 0.1s. what is the change in?

Answer 1

The change in velocity is 2m/s

Given ,

mass of baseball m = 0.5kg

force on baseball F = 10 N

Duration .i.e. time t = 0.1s

To find here change in velocity =?

Solution,

The impulse(J) of an object is equal to,

J = F× T

Where J is the impulse of the baseball and F is force on baseball at time t.

The impulse is equal to the change in momentum of the baseball and its unit is (N.s) Newton -second. it is a vector quantity therefore the dimension is [LMT⁻¹]. Then the impulse j is given as ,

J = m(v-u)

Here J is impulse ,m is mass, (v-u) is change in velocity .From equating the both impulse equations then can be write as,

m(v-u) = F× t

(v -u) =( F × t)/m

(v -u) = (10N× 0.1 s)/0.5k

(v -u) = 2m/s

Hence the change in velocity (v -u) of baseball is 2m/s.

• A 0.5kg baseball experiences a 10n force for a duration of 0.1s. what is the change in velocity of the baseball ?

To know more about impulse

brainly.com/question/26739863

#SPJ4