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2 years ago

In a bell-shaped curve, the x-axis (horizontal direction) of the graph represents which of the following

1 answer:

4 0

X-axis represents the value of a particular characteristic; characteristics of an organism can include such traits as size and color.

<h3>What is a bell-shaped curve?</h3>

A typical sort of distribution for a variable is the bell curve, commonly referred to as the normal distribution. The normal distribution graph, which has a symmetrical bell-shaped curve, is what gave rise to the phrase "bell curve."

The highest point on the curve, or the top of the bell, denotes the most likely outcome in a set of data (its mean, mode, and median), while all other potential outcomes are symmetrically distributed around the mean, resulting in a downward-sloping curve on each side of the peak. The bell curve's standard deviation provides information about its width.

The x-axis represents a variable's value, while the y-axis provides information about the likelihood that we will see that value.

I understand the question you are looking for is this:

In a bell-shaped curve, the x-axis (horizontal direction) of the graph represents which of the following?

a. The value of a particular characteristic; characteristics of an organism can include such traits as size and color.

b. The number of individuals

c. Time

Learn more about bell-shaped curve here:

brainly.com/question/24182600

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Why does the solar system consist of small planets orbiting close to sun and larger on more distant

ahrayia [7]

Answer:

The inner planets are smaller and rockier

Explanation:

Astronomers divide the planets into two groups in Solar system, the inner planets and outer planets. The inner planets are smaller and rockier and it is closer to the sun. The outer planets are larger , further far away and made of gas

The inner planets are Mercury, Venus , Earth and Mars. The outer planets Jupiter , Saturn , Uranus and Neptune comes after an asteroid belt. In some other planetary systems the gas are close to the sun.

particles in a disk of gas and dust will form Planets. If they orbit the star they are colliding and sticking. The stars wind blows away their gases . So the nearest planets to starts are rockier.

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3 years ago

Earthquakes usually occur on or near: cities roads fault lines lakes

vivado [14]

Answer:

Fault lines

Explanation:

Earthquakes are most likely to occur near or on fault lines. A great example of this is the ring of fire, a gigantic fault line that gives catastrophic earthquakes.

3 0

3 years ago

Read 2 more answers

El salto con garrocha es practicado por:

Ulleksa [173]

D. Solo a y b
De nada

8 0

3 years ago

Two 4.0 kg masses are 1.0 m apart on a frictionless table. Each has 1.0 μC of charge.What is the magnitude of the electric force

xeze [42]

Coulomb's law:

Force = (<span>8.99×10⁹ N m² / C²<span>) · (charge₁) · (charge₂) / distance²

= (</span></span><span>8.99×10⁹ N m² / C²<span>) (1 x 10⁻⁶ C) (1 x 10⁻⁶ C) / (1.0 m)²

= (8.99×10⁹ x 1×10⁻¹² / 1.0) N

=    8.99×10⁻³ N

=    0.00899 N repelling.

Notice that there's a lot of information in the question that you don't need.
It's only there to distract you, confuse you, and see whether you know
what to ignore.

-- '4.0 kg masses'; don't need it.
   Mass has no effect on the electric force between them.

-- 'frictionless table'; don't need it.
   Friction has no effect on the force between them,
only on how they move in response to the force.
</span></span>

7 0

3 years ago

A brick falls to the ground. if the time for the collision of the brick and the ground is increased by a factor of 4, the force

melomori [17]

Answer:

By a factor of 1/4.

Explanation:

The impulse force that applies to an object undergoing rapid deceleration just before coming to a stop on the ground is given by the following formula,

$\\\begin{aligned}\\\small F &=\small \frac{\Delta (mV)}{\Delta T}\end{aligned}$

in which $\small \Delta (mV)$ , $\small \Delta t$ represent the change in momentum and the time taken for that change.

If one increases the time that is taken for the momentum change (which remains constant for this situation) by a factor 4 and if that new force is represented by $\small F_1$ , the following manipulation confirms the answer to this question.

$\begin{aligned}\\\small F_1 &=\small \frac{\Delta (mV)}{4\Delta t}\\\\&=\small \frac{1}{4}\times\bigg[\frac{\Delta (mV)}{\Delta t}\bigg]\\\\&=\small \frac{1}{4}F\end{aligned}$

Here $\small F$ is the force that was applied to the object previously.

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4 0

1 year ago