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SCORPION-xisa [38]

3 years ago

12

Meteoroids are small objects in space, usually made of rock or metal. These bodies often get close to a planet and fall through

its atmosphere. A burning streak of light, called a , is visible as it falls through the sky. Sometimes the object does not burn up completely and a part of it survives the fall to the planet’s surface. These rocky bodies, called , are studied by scientists to gain a better understanding of our solar system. NextReset

1 answer:

rewona [7]3 years ago

5 0

First chose is meteor and the second one is asteroids

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A basketball of mass 0.608 kg is dropped from rest from a height of 1.37 m. It rebounds to a height of 0.626 m.

kenny6666 [7]

Answer:

a) $|\Delta E|=4.58\: J$

b) $F=61.90\: N$

Explanation:

a)

We can use conservation of energy between these heights.

$\Delta E=mgh_{2}-mgh_{1}=mg(h_{2}-h_{1})$

$\Delta E=0.608*9.81(0.6026-1.37)$

Therefore, the lost energy is:

$|\Delta E|=4.58\: J$

b)

The force acting along the distance create a work, these work is equal to the potential energy.

$W=\Delta E$

$F*d=mgh$

Let's solve it for F.

$F=\frac{mgh}{d}$

$F=\frac{0.608*9.81*1.37}{0.132}$

Therefore, the force is:

$F=61.90\: N$

I hope is helps you!

6 0

3 years ago

The Hubble space telescope has been maintained by which of these?

ra1l [238]

The answer to your question is NASA's Hubble Space Telescope<span> is the first major infrared-optical-ultraviolet</span>telescope<span> to be placed into orbit around the Earth.And it Located high above Earth's obscuring atmosphere, the </span>telescope has<span> provided the clearest views of the universe yet obtained in optical astronomy. Its in the International Space Station
Hope this helps</span>

6 0

3 years ago

Burning a canful of petrol or dropping it. which is likely to release most energy?

Neporo4naja [7]

Answer:

Burning of canful of petrol will release more energy

Explanation:

If you like my answer than please mark me brainliest

5 0

3 years ago

How much of earths gravitational force acts on everyone and everything onboard of the international space station?

liraira [26]

B) Approx. 90%

The actual value is 0.89g

4 0

3 years ago

A 0.29 kg particle moves in an xy plane according to x(t) = - 19 + 1 t - 3 t3 and y(t) = 20 + 7 t - 9 t2, with x and y in meters

Artist 52 [7]

Answer:

Part a)

$F = 7.76 N$

Part b)

$\theta = -137.7 degree$

Part c)

$\theta = -127.7 degree$

Explanation:

As we know that acceleration is rate of change in velocity of the object

So here we know that

$x = -19 + t - 3t^3$

$y = 20 + 7t - 9t^2$

Part a)

differentiate x and y two times with respect to time to find the acceleration

$a_x = \frac{d^2}{dt^2}(-19 + t - 3t^3)$

$a_x = \frac{d}{dt}(0 +1 - 9t^2)$

$a_x = -18t$

$a_y = \frac{d^2}{dt^2}(20 + 7t - 9t^2)$

$a_y = \frac{d}{dt}(0 +7 - 18t)$

$a_y = -18$

Now the acceleration of the object is given as

$\vec a = (-18t)\hat i + (-18)\hat j$

at t= 1.1 s we have

$\vec a = -19.8 \hat i - 18 \hat j$

now the net force of the object is given as

$\vec F = m\vec a$

$\vec F = (0.29 kg)(-19.8 \hat i - 18 \hat j)$

$\vec F = -5.74 \hat i - 5.22 \hat j$

now magnitude of the force will be

$F = \sqrt{5.74^2 + 5.22^2} = 7.76 N$

Part b)

Direction of the force is given as

$tan\theta = \frac{F_y}{F_x}$

$tan\theta = \frac{-5.22}{-5.74}$

$\theta = -137.7 degree$

Part c)

For velocity of the particle we have

$v_x = \frac{dx}[dt}$

$v_x = (0 +1 - 9t^2)$

$v_y = \frac{dy}{dt}$

$v_y = (0 +7 - 18t)$

now at t = 1.1 s

$\vec v = -9.89\hat i - 12.8 \hat j$

now the direction of the velocity is given as

$\theta = tan^{-1}(\frac{v_y}{v_x})$

$\theta = tan^{-1}(\frac{-12.8}{-9.89})$

$\theta = -127.7 degree$

7 0

3 years ago