All categories

3 years ago

Determine the speed of sound on a rainy day with the temperature of 18 degrees celsius..

Physics

1 answer:

Troyanec [42]3 years ago

6 0

Answer:

Answer:

= 338.2 m/s

Explanation:

vs= 331 + T (0.6m/s)

= 331 + 12 °C (0.6m/s)

= 331 + 7.2m/s

= 338.2 m/s

Explanation:

You might be interested in

The atomic mass of an element is A. twice the number of protons in one atom of the element. B. the sum of the protons and neutro

krek1111 [17]

B. the sum of the protons and the neutrons in one atom of the element

3 0

3 years ago

Read 2 more answers

To keep the calculations fairly simple, but still reasonable, we shall model a human leg that is 92.0 cm long (measured from the

lorasvet [3.4K]

Answer:

Xc = 64.27 cm, Yc = 0 cm, Xc = 27.73 cm, Yc = 18.27 cm

Explanation:

A human leg is 92 cm long equally divided into two parts (upper leg and lower leg) that is both are 46 cm long

M1 = 8.35 kg

M2 = 5.50 kg

A. Starting from hip joint, when the leg is placed horizontally, the X coordinate of centre of mass will be

Xc = (m1x1 + m2x2) / m1 + m2

Xc = (8.35x46 + 5.50 x 92) / 8.35 + 5.50

( here we took x2 = 92 cm because we are measuring length from the hip joint, that means length at hip joint is 0 and at the foot 92 cm)

Xc = 890.1 / 13.85

Xc = 64.27 cm

B. Yc = (y1m1 + y2m2) / m1 + m2

Yc = (0x8.35 + 0x5.50) / 8.35 + 5.50

( here y1 and y2 are 0 because the leg is placed horizontally that means in X direction so none of the leg component is in Y direction)

Yc = 0 cm

C. Xc = (m1x1 + m2x2) / m1 + m2

Xc = (8.35x46 + 5.50x0) / 8.35 + 5.50

(here x2 is taken 0 because the other half leg is bent vertically that means it is in Y direction so its X component is 0)

Xc = 384.1 / 13.85

Xc = 27.73 cm

D. Yc = (m1y1 + m2y2) / m1 + m2

Yc = (8.35x0 + 5.50x46) / 8.35 + 5.50

(here y1 is zero because the upper leg is in X direction and y2 is taken 46 cm because starting measuring from hip joint 46 cm of length of lower leg is in Y direction)

Yc = 253/13.85

Yc = 18.27 cm

7 0

3 years ago

Two containers have a substantial amount of the air evacuated out of them so that the pressure inside is half the pressure at se

adoni [48]

Answer:

$(a)\ F_{No} = [P_{No} - \frac{P_{area}}{2}]* A$

$(b)\ F_{No} = 771.125N$

Explanation:

Given

$d_D = 6000ft$ ---- Altitude of container in Denver

$A = 0.0155m^2$ -- Surface Area of the container lid

$P_D = 79000Pa$ --- Air pressure in Denver

$P_{No} = 100250Pa$ --- Air pressure in New Orleans

<em>See comment for complete question</em>

Solving (a): The expression for $F_{No$

Force is calculated as:

$F = \triangle P * A$

The force in New Orleans is:

$F_{No} = \triangle P * A$

Since the inside pressure is half the pressure at sea level, then:

$\triangle P = P_{No} - \frac{P_{area}}{2}$

Where

$P_{area} = 101000Pa$ --- Standard Pressure

Recall that:

$F_{No} = \triangle P * A$

This gives:

$F_{No} = [P_{No} - \frac{P_{area}}{2}]* A$

Solving (b): The value of $F_{No$

In (a), we have:

$F_{No} = [P_{No} - \frac{P_{area}}{2}]* A$

Where

$A = 0.0155m^2$

$P_{No} = 100250Pa$

$P_{area} = 101000Pa$

So, we have:

$F_{No} = [100250 - \frac{101000}{2}] * 0.0155$

$F_{No} = [100250 - 50500] * 0.0155$

$F_{No} = 49750* 0.0155$

$F_{No} = 771.125N$

4 0

3 years ago

A bar of length L = 8 ft and midpoint D is falling so that, when θ = 27°, ∣∣v→D∣∣=18.5 ft/s , and the vertical acceleration of p

777dan777 [17]

Answer:

alpha=53.56rad/s

a=5784rad/s^2

Explanation:

First of all, we have to compute the time in which point D has a velocity of v=23ft/s (v0=0ft/s)

$v=v_0+at\\\\t=\frac{v}{a}=\frac{(23\frac{ft}{s})}{32.17\frac{ft}{s^2}}=0.71s$

Now, we can calculate the angular acceleration (w0=0rad/s)

$\theta=\omega_0t +\frac{1}{2}\alpha t^2\\\alpha=\frac{2\theta}{t^2}$

$\alpha=\frac{27}{(0.71s)^2}=53.56\frac{rad}{s^2}$

with this value we can compute the angular velocity

$\omega=\omega_0+\alpha t\\\omega = (53.56\frac{rad}{s^2})(0.71s)=38.02\frac{rad}{s}$

and the tangential velocity of point B, and then the acceleration of point B:

$v_t=\omega r=(38.02\frac{rad}{s})(4)=152.11\frac{ft}{s}\\a_t=\frac{v_t^2}{r}=\frac{(152.11\frac{ft}{s})^2}{4ft}=5784\frac{rad}{s^2}$

hope this helps!!

6 0

3 years ago

Read 2 more answers

two ice skaters push each other, and move in opposite directions. the mass of one is 75 kg, and his speed is 2 m/s. if the mass

sattari [20]

momentum conservation

75x2 = 30 x her speed

75x2/30=150/30=5m/s

7 0

4 years ago