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3 years ago

A water balloon is dropped off the top of a building and bursts when it hits

Physics

1 answer:

Dennis_Churaev [7]3 years ago

5 0

Answer:

The building is 176.4 meters high.

Explanation:

We use the formula for kinematics of an accelerated object (in this case acceleration of gravity):

Distance travelled = 1/2 g t^2

Distance travelled = 1/2 9.8 (6)^2 = 176.4 meters

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A boat travels at 15 m/s in a direction 45 east of north for an hour The boat then turns and tra

Dmitriy789 [7]

Answer:

V1 = 15m/s[45o E of N.] = 45o N. of E.

V2 = 18m/s[5o N. of E.].

Vr = 15m/s[45o] + 18m/s[5o].

Vr = 15*Cos45+15*sin45 + 18*Cos5+18*sin5.

Vr = (10.61+10.61i) + (17.93+1.57i) = 28.54 + 12.18i.

Magnitude = sqrt(28.54^2 + 12.18^2) =

Tan A = Y/X = 12.18/28.54 = 0.42887. A =

0 2

posted by Henry

Apr 8, 2017

31 m/s

23 ° north of east

Explanation:

7 0

3 years ago

A 0.500 kg ball is dropped from rest at a point 1.20 m above the floor. The ball rebounds straight upward to a height of 0.700 m

KatRina [158]

To solve this problem we will apply the concepts related to energy conservation. With this we will find the speed before the impact. Through the kinematic equations of linear motion we will find the velocity after the impact.

Since the momentum is given as the product between mass and velocity difference, we will proceed with the velocities found to calculate it.

Part A) Conservation of the energy

$mgh = \frac{1}{2} mv^2$

$v_1 = \sqrt{2gh}$

$v_1 = \sqrt{2(9.8)(1.20)}$

$v_1 = 4.84m/s$

$\therefore v_1 = -4.84/s \rightarrow \text{Negative direction downward}$

Part B) Kinematic equation of linear motion,

$v_2^2 = u_0^2 +2a\Delta y$

Here

v= 0 Because at 1.5m reaches highest point, so v=0

$0 = u_2^2 +2(-9.8)(0.7)$

$u_2 = 3.7m/s$

Therefore the velocity after the collision with the floor is 3.7m/s

PART C) Total change of impulse is given as,

$J = P_2 -P_1$

$J = mU_2-mV_1$

$J = m(U_2-V_1)$

$J = (0.5)(3.7-(-4.84))$

$J = 4.27kg \cdot m/s \rightarrow \text{Upward because is positive}$

6 0

4 years ago

Will the velocity of a box change as it moves across the surface with no friction?Explain

nevsk [136]

The velocity will remain unchanged (Newton’s 1st Law) unless a force acts on it. If no friction force, then the velocity remains constant.

3 0

3 years ago

The wavelength of light visible to the human eye is on the order of 5 x 10-7 m. if the speed of light in air is 3 x 108 m/s, fin

juin [17]

The frequency of light wave is 0.6*10^15 Hz.

The relation between the speed of light, frequency, and wavelength is given as

c=λν

Plugging the values in the above equation

3*10^8=5*10^(-7)*ν

ν=0.6*10^15 Hz.

Therefore the frequency of the light wave is 0.6*10^15 Hz.

6 0

4 years ago

"In this lesson, you learned about renewable energy resources and nonrenewable energy resources. Think about the resources discu

Nutka1998 [239]

U can also add solar energy and hydro energy. Solar energy is by using the sun, while hydro is by using the force of water.
This is how hydro energy works:
its is usually built near a waterfall, OK so when the water falls of the cliff of the water fall , it creates a force which helps turn the generator and then it is carried into poles of electricity.
Hope this helps plus i gave u extra point Good luck :)

5 0

3 years ago