Answer:
Step-by-step explanation:
Given [Missing from the question]
Equation:
Interval:
Required
Determine the values of 
The given expression:
... shows that the value of is positive
The cosine of an angle has positive values in the first and the fourth quadrants.
So, we have:
Take arccos of both sides
--- In the first quadrant
In the fourth quadrant, the value is:
So, the values of in degrees are:
Convert to radians (Multiply both angles by 
)
So, we have:
The full range is
(length
), so the half range is
. The half range sine series would then be given by
where
Essentially, this is the same as finding the Fourier series for the function
Integrating by parts yields
So the half range sine series for this function is simply
-(4/5)*(3/7)*(15/16)*(-14/9) [two negatives make one positive]
=(4*3*15*14)/(5*7*16*9) [simplify 4/16]
=(3*15*14)/(5*7*4*9)
=(3*3*14)/(7*4*9)
=(14)/(7*4)
=(2)/(4)
=1/2
1,388.26-200.86=1,187.40
If she makes 79.16 you need to multiply until you get more or exactly to 1,187.40
I’m order to succeed this amount she must work (15 WEEKS) to save enough money.
