The length of the line segment BC is 31.2 units.
<h2>Given that</h2>
Triangle ABC is shown.
Angle ABC is a right angle.
An altitude is drawn from point B to point D on side AC to form a right angle.
The length of AD is 5 and the length of BD is 12.
<h3>We have to determine</h3>
What is the length of Line segment BC?
<h3>According to the question</h3>
The altitude of the triangle is given by;

Where x is DC and y is 5 units.
Then,
The length DC is.

Squaring on both sides

Considering right triangle BDC, use the Pythagorean theorem to find BC:

Hence, the length of the line segment BC is 31.2 units.
To know more about Pythagoras Theorem click the link given below.
brainly.com/question/26252222
Pretty sure the answer is 18
3^2+3^2=9+9=18 (with a square root)
Jay walks 2 1/4 miles which if you double it so the denominators are e same for both 2 1/4 and 1 1/8 then your answer will be 18/8 (Jay) and 9/8 (Reggie). Meaning that Reggie walks have the distance Jay walks.
6(y+8) is the answer but you didn’t finish the equation so
You can draw a right triangle with the informatio.
The vertical change in elevation (unknown) is the opposed leg to the angle 15°
The distance from the surveyor to the point vertically below the point on the mountain is the adjacent leg = 6 miles.
Then tan(15°) = x / 6 => x = 6tan(15) = 1.61 miles
Answer: 1.61 miles