<span>The angular momentum of a particle in orbit is
l = m v r
Assuming that no torques act and that angular momentum is conserved then if we compare two epochs "1" and "2"
m_1 v_1 r_1 = m_2 v_2 r_2
Assuming that the mass did not change, conservation of angular momentum demands that
v_1 r_1 = v_2 r_2
or
v1 = v_2 (r_2/r_1)
Setting r_1 = 40,000 AU and v_2 = 5 km/s and r_2 = 39 AU (appropriate for Pluto's orbit) we have
v_2 = 5 km/s (39 AU /40,000 AU) = 4.875E-3 km/s
Therefore, </span> the orbital speed of this material when it was 40,000 AU from the sun is <span>4.875E-3 km/s.
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The angle of reflection is "60°".
Here we apply the law of the concept of reflection then we get the final answer easily.
The angle of incident = angle of reflection
Then, the Angle of the incident =60°
What is reflection?
- Reflection is the phenomenon of light rays returning to the source after striking an obstruction.
- It resembles the way a ball bounces when we toss it on a hard surface.
- Some of the light rays that strike an item are reflected, some of them travel through it, and the remainder are absorbed by the object.
- The given values are:Light from a monochromatic source,= 560 nm
- The angle of incidence,= 60°
- The surface of fused quartz (n),= 1.56
- When a light ray does exist on a flat surface, the law or idea of reflection should apply since it includes both the reflected and "normal" light rays at the mirror surface.
- According to the above law,Angle of incident = angle of reflection
- Then, Angle of incident =60°.
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Explanation:
130km = (0.621 * 130) mi = 80.73 mi
So if you drive at 80.73 mph you will get a ticket for speeding over the limit.
Answer:
151.2 m/s
Explanation:
m1 = 0.020 kg
m2 = 2.5 kg
vf = 1.2 m/s
m1v1 +m2v2 = (m1 +m2)vf
0.020v1 + 0 = (0.020 +2.5)(1.2)
---> 151.2 m/s
