Question

What is the current in the circuit at the instant the capacitor begins to charge (the instant the switch is first closed)?

Answer 1

Complete  Question

The  complete question is shown on the first uploaded image

Answer:

The current is  $I = 4.2 \ A$

Explanation:

From the question we are told that

    The  voltage of battery is  $V = 25 V$

     The  capacitance of capacitor is  $C = 15 \mu F$

      The resistance of the resistor is  $R = 6 \Omega$

Generally the current at the instant the capacitor starts charging is  

             $I = \frac{V}{R}$

substituting values

           $I = \frac{25}{6}$

         $I = 4.2 \ A$