A proton moves from left to right across the screen at speed v0. Then a uniform magnetic field of strength 0.80 T is directed in
to the screen. What is the direction of the force on the proton?
1 answer:
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Answer:
81.8 m/s
Explanation:
The initial velocity of the plane is:
(toward east)
So, decomposing along the x- and y- directions:
(we took east as positive x-direction and north as positive y-direction)
The acceleration is
(northwest, so the angle with the positive x-direction is 135 degrees)
Decomposing it along the two directions:
So the two components of the velocity after a time t = 25.0 s will be
So, the magnitude of the velocity of the plane will be