Answer:
4375 N, 7875 N
Explanation:
since the body is equilibrium
total upward force = total downward force
w weight of the bridge = FL + FR
when the car was introduced,
total downward force = total upward force
FL₁ + FR₁ = w + (m × acceleration due to gravity) with w = FL + FR
then FL₁ + FR₁ = FL + FR + Mcg
FL₁ + FR₁ - FL - FR = Mcg
ΔFL + ΔFR = 1250 × 9.8 = 12250 N
taken the left as the pivot point and using the principle of moment
ΔFR × 14 m = 12250 N × 5 m + (ΔFL × 0 m) since the left is the pivot point.
ΔFR = 61250 / 14 = 4375 N
but
ΔFL + ΔFR = 12250 N
ΔFL = 12250 - 4375 = 7875 N
Answer
given,
L(t) = 10 - 3.5 t
mass of particle = 2 Kg
radius of the circle = 3.1 m
a) torque
τ = 
τ = 
τ = -3.5 N.m
Particle rotates clockwise as i look down the plane. Hence, its angular velocity is downward.
L decreases the angular acceleration upward. so, net torque is upward.
b) Moment of inertia of the particle
I = m R^2
I = 2 x 3.1²
I = 19.22 kg.m²
L = I ω
ω = 
ω = 
ω = 
A = 0.52 rad/s B = -0.182 rad/s²
Given: Wavelength λ = 410 nm convert to Meters m = 4.10 x 10⁻⁷ m
Speed of light c = 3 x 10⁸ m/s
Required: Frequency f = ?
Formula: c = λf
f = c/λ
f = 3 x 10⁸ m/s/4.10 x 10⁻⁷ m
f = 7.32 x 10¹⁴/s or 732 Thz (Terahertz)
519.75N
explanation: good luck on whatever assignment
