Boyle’s law is P1V1 = P2V2. This shows that pressure and volume have an inverse relationship, so increase in pressure causes a decrease in volume. B is your answer
Answer:
option (b)
Explanation:
for a telescope, the object is placed very far from the objective lens so the focal length of objective is large and the eye piece is of short focal length.
So, long focal length objective and short focal length eyepiece.
Option (b) is correct.
This process is called a quantization error. It is the difference between the analog signal and digital values.
<h3>What is a quantization error?</h3>
Quantization error refers to the difference between analog signals and their closest digital values during the process of sampling.
This process (quantization error) involves an A/D converter, i.e., an analog to a digital converter (ADC).
The A/D converter is a type of converter that acts by capturing analog signals at given fixed time intervals.
Learn more about quantization error here:
brainly.com/question/5601999
(a) The frequency of the motion after the collision is 0.71 Hz.
(b) The maximum angular displacement of the motion after the collision is 16.3⁰.
<h3>Speed of the 2.2 kg ball when it collides with 2.7 kg ball</h3>
The speed of the 2.2 kg ball which was initially 10 cm higher that 2.7 kg ball is calculated as follows;
K.E = P.E
¹/₂mv² = mgh
v² = 2gh
v = √2gh
v = √(2 x 9.8 x 0.1)
v = 1.4 m/s
<h3>Final speed of both balls after collision</h3>
The final speed of both balls after the collision is determined from the principle of conservation of linear momentum.
Pi = Pf
m₁v₁ + m₂v₂ = vf(m₁ + m₂)
2.2(1.4) + 2.7(0) = vf(2.2 + 2.7)
3.08 = 4.9vf
vf = 3.08/4.9
vf = 0.63 m/s
<h3>Maximum displacement of the balls after the collision</h3>
P.E = K.E

<h3>Maximum angular displacement</h3>
The maximum angular displacement of the balls after the collision is calculated as follows;

<h3>Frequency of the motion</h3>

Learn more about maximum angular displacement here: brainly.com/question/13665036