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S_A_V [24]
3 years ago
8

In an isolated system, two cars, each with a mass of 1,500 kg, collide. Car 2 is

Physics
2 answers:
AleksAgata [21]3 years ago
8 0

Answer: Correct Answer is 10 m/s

Explanation:

mixer [17]3 years ago
3 0

its prolly d muy guy

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Hey can yall help me out in dis
Karolina [17]

Answer:

Scientific method

Explanation:

5 0
3 years ago
What momentum does a 70 kg person running 10m/s (a fast sprint) have ?
gogolik [260]

Momentum = (mass) x (speed)

Momentum = (70 kg) x (10 m/s)

<em>Momentum = 700 kg-m/s</em>

8 0
3 years ago
The resistance, R, of a wire varies directly as its length and inversely as the square of its diameter. If the resistance of a w
lbvjy [14]

R is proportional to the length of the wire:

R ∝ length

R is also proportional to the inverse square of the diameter:

R ∝ 1/diameter²

The resistance of a wire 2700ft long with a diameter of 0.26in is 9850Ω. Now let's change the shape of the wire, adding and subtracting material as we go along, such that the wire is now 2800ft and has a diameter of 0.1in.

Calculate the scale factor due to the changed length:

k₁ = 2800/2700 = 1.037

Scale factor due to changed diameter:

k₂ = 1/(0.1/0.26)² = 6.76

Multiply the original resistance by these factors to get the new resistance:

R = R₀k₁k₂

R₀ = 9850Ω, k₁ = 1.037, k₂ = 6.76

R = 9850(1.037)(6.76)

R = 69049.682Ω

Round to the nearest hundredth:

R = 69049.68Ω

8 0
3 years ago
If we decrease the amount of force, and kelp all other factors the same, what will happen to the amount of work?
Artist 52 [7]

Answer:

Distance will decrease and work will decrease:

F = m a      Newton's Second Law

a = F / m       decreasing force will decrease acceleration

S = 1/2 a t^2 = 1/2 (F / m) t^2     distance traveled will decrease as force        decreases

W = F * S       work will decrease as both force and distance decrease

8 0
3 years ago
Use V=Voe^-t/RC and T=RC to derive T1/2=Tln2
Ksju [112]
Enclosed is some guidance algebra.I find this q a little confusing. It quotes "RC" which usually makes me think of electrical circuits and time constants based on converting calculating RC value and equating that to t for one time constant then 2RC for two time constants etc. The theory being that after 5 time constants - 5RC - a circuit is stable. BUT, this q then goes on to mention HALF LIFE. The curves for both half life and time constant are both exponential, as in the number e to the power of something, but the algebra is slightly different. I hope my algebra is ok.

3 0
3 years ago
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