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katen-ka-za [31]
3 years ago
12

What is the percent by mass of Ca in calcium chloride, CaCI2 (show your work)

Chemistry
1 answer:
adoni [48]3 years ago
5 0

Answer:

\boxed{ \tt{ \frac{Ca}{CaCl_2}  \times  \frac{100}{1} }}

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2.What is the scientific method and how does it work?
never [62]

Answer:A hypothesis is a conjecture, based on knowledge obtained while seeking answers to the question

Explanation:

he process of the scientific method involves making conjectures (hypotheses), deriving predictions from them as logical consequences, and then carrying out experiments or empirical observations based on those predictions.

6 0
3 years ago
EXTRA POINTSSS 1. A solution at 25 degrees Celsius is 1.0 × 10–5 M H3O+. What is the concentration of OH– in this solution?
AlekseyPX

Answer:

Concentration of OH⁻:

1.0 × 10⁻⁹ M.

Explanation:

The following equilibrium goes on in aqueous solutions:

\text{H}_2\text{O}\;(l)\rightleftharpoons \text{H}^{+}\;(aq) + \text{OH}^{-}\;(aq).

The equilibrium constant for this reaction is called the self-ionization constant of water:

K_w = [\text{H}^{+}]\cdot[\text{OH}^{-}].

Note that water isn't part of this constant.

The value of K_w at 25 °C is 10^{-14}. How to memorize this value?

  • The pH of pure water at 25 °C is 7.
  • [\text{H}^{+}] = 10^{-\text{pH}} = 10^{-7}\;\text{mol}\cdot\text{dm}^{-3}
  • However, [\text{OH}^{-}] = [\text{H}^{+}]=10^{-7}\;\text{mol}\cdot\text{dm}^{-3} for pure water.
  • As a result, K_w = [\text{H}^{+}] \cdot[\text{OH}^{-}] = (10^{-7})^{2} = 10^{-14} at 25 °C.

Back to this question. [\text{H}^{+}] is given. 25 °C implies that K_w = 10^{-14}. As a result,

\displaystyle [\text{OH}^{-}] = \frac{K_w}{[\text{H}^{+}]} = \frac{10^{-14}}{1.0\times 10^{-5}} = 10^{-9} \;\text{mol}\cdot\text{dm}^{-3}.

8 0
3 years ago
0.00105 liters is the same as how many cm and ml
Ainat [17]
The answer is 1.05 cubic centimeters and 1.05 mL (1 cubic centimeter is equal to 1 mL)
8 0
4 years ago
OT protons (d) (a) and (b)
insens350 [35]
<h2>b is the correct answer</h2>

according In my course I studying it all

6 0
3 years ago
Read 2 more answers
All the following are steps included in linking amino acids to form chains except
ss7ja [257]
The correct option is D.
During peptide formation, when two amino acids come together, a hydrogen atom and two molecules of oxygen are released in form of water molecules. The amino acid that present the carboxyl group to the reaction loses an hydroxyl group while the amino acid that present the amino group to the reaction loses a hydrogen.
4 0
3 years ago
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