All categories

3 years ago

An element's atomic number is 77. How many protons would an atom of this element have? protons

Physics

2 answers:

bulgar [2K]3 years ago

6 0

Your answer is 55 protons.

salantis [7]3 years ago

5 0

The number of protons would be 77. i know this sounds wrong but it may be correct. i looked it up. the atomic mass would be 192.217 atomic mass units. the name of this is Iridium. the number of neutrons would be 115.
hope this helps u.

You might be interested in

List atleast to conditions that could cause the pressure inside a sealed container of gas to increase

hjlf

There are exactly three ways that could happen:

1). The container was heated, and the gas inside it got warmer.

2). Some part inside the container moved somehow, and made
      the inside volume smaller, so the gas got scrunched into a
      smaller space.

3). Somebody pumped some more gas into the container, so
      a greater amount of gas had to live in the same space.

8 0

3 years ago

Define density and give its SI unit

3241004551 [841]

Answer:

Density is defined as mass per unit volume. its SI unit is: kg/m³

Explanation:

8 0

1 year ago

Read 2 more answers

One electron collides elastically with a second electron initially at rest. After the collision, the radii of their trajectories

morpeh [17]

Answer:

63.750KeV

Explanation:

We are given that

Initial velocity of second electron, $u_2=0$

Radius, $r_1=0$

$r_2=2.3 cm=\frac{2.3}{100}=0.023 m$

1 m=100 cm

Magnetic field,B=0.0370 T

We have to determine the energy of the incident electron.

Mass of electron, $m=9.1\times 10^{-31} kg$

Charge on an electron, $q=-1.6\times 10^{-19} C$

Velocity, $v=\frac{Bqr}{m}$

Using the formula

Speed of electron, $v_1=\frac{Bqr_1}{m}=\frac{0.0370\times 1.6\times 10^{-19}\times 0}{9.1\times 10^{-31}}=0$

Speed of second electron, $v_2=\frac{0.0370\times 1.6\times 10^{-19}\times 0.023}{9.1\times 10^{-31}}$

$v_2=1.5\times 10^8 m/s$

Kinetic energy of incident electron= $\frac{1}{2}mv^2_1+\frac{1}{2}mv^2_2$

Kinetic energy of incident electron= $0+\frac{1}{2}(9.1\times 10^{-31})(1.5\times 10^8)^2=1.02\times 10^{-14} J$

Kinetic energy of incident electron= $\frac{1.02\times 10^{-14}}{1.6\times 10^{-19}}=63750eV=\frac{63750}{1000}=63.750KeV$

1KeV=1000eV

3 0

3 years ago

How do scientists decide how they gather information

kogti [31]

The scientific method. When conducting research, scientists use the scientific method to collect measurable, empirical evidence in an experiment related to a hypothesis (often in the form of an if/then statement), the results aiming to support or contradict a theory.

3 0

3 years ago

Help please help!!!!!!!!

Sidana [21]

1. Electron

2. Neutron

3. Nucleus

4. Atom

5. Molecule

6 0

2 years ago