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-Dominant- [34]
3 years ago
6

Describe the conditions necessary for sublimation to occur​ please help

Physics
1 answer:
katovenus [111]3 years ago
6 0

Answer:

Sublimation occurs more readily when certain weather conditions are present, such as low relative humidity and dry winds. Sublimation also occurs more at higher altitudes, where the air pressure is less than at lower altitudes. Energy, such as strong sunlight, is also needed.

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When you pick a book up off the floor you are tranfering __________ energy from your hands to the ____________ energy of the boo
MakcuM [25]
When you pick a book off the floor you are transferring kinetic energy from your hands to the potential energy of the book.
3 0
4 years ago
A hydraulic system at the mechanic shop can perform up to 180,000 joules of work in a day. if throughout the day it can lift 10
snow_tiger [21]

Answer:

9,000 N.

Explanation:

Workdone can be defined as the ability to do work. It is also the product of the force and the distance it is being moved.

Mathematically,

W = F * d

= 180,000/2

= 90,000 N.

Weight of the 10 cars = 90,000 N.

Weight of a car = 90000/10

= 9,000N.

5 0
4 years ago
How many nutrons are in an atom of copper
xeze [42]

Answer:

35 neutrons are in an atom of copper

8 0
3 years ago
Read 2 more answers
A 1.5m wire carries a 6 A current when a potential difference of 61 V is applied. What is the resistance of the wire?
Alisiya [41]

Resistance = (voltage) / (current)

For this piece of wire . . .

Resistance = (61 volts) / (6 Amperes)

Resistance = (61/6) (V/A)

<em>Resistance = (10 and 1/6) ohms</em>

Since you know the voltage and current, the length doesn't matter.

7 0
3 years ago
A 6.00 kg object is lifted vertically through a distance of 5.25 m by a light string under a tension of 80.0 N. Find: (2 marks)
jeka57 [31]

Explanation:

It is given that,

Mas of the object, m = 6 kg

It is lifted through a distance, h = 5.25 m

Tension in the string, T = 80 N

(a) By considering the free body diagram of the object, the forces can be equated as :

T-mg=ma

a=\dfrac{T-mg}{m}

a=\dfrac{80-6\times 9.8}{6}

a=3.33\ m/s^2

Work done by tension, W_t=F\times h

W_t=80\times 5.25

W_t=420\ J

(b) Work done by gravity, W_g=mgh

W_g=6\times 9.8\times 5.25

W_g=308.7\ J

(c) Let v is the final speed of the object and u = 0

v=\sqrt{2ah}

v=\sqrt{2\times 3.33\times 5.25}

v = 5.91 m/s

Hence, this is the required solution.

7 0
4 years ago
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