Here is the full question:
Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/min, and the circulated air is then pumped out at the same rate. If there is an initial concentration of 0.2% carbon dioxide, determine the subsequent amount in the room at any time.
What is the concentration at 10 minutes? (Round your answer to three decimal places.
Answer:
0.046 %
Explanation:
The rate-in;

= 0.8
The rate-out
= 
= 
We can say that:

where;
A(0)= 0.2% × 6000
A(0)= 0.002 × 6000
A(0)= 12

Integration of the above linear equation =

so we have:



∴ 
Since A(0) = 12
Then;



Hence;



∴ the concentration at 10 minutes is ;
=
%
= 0.0456667 %
= 0.046% to three decimal places
Answer:
HELIUM IS HE ANSWER
Explanation:
<em>G</em><em>O</em><em>O</em><em>D</em><em> </em><em>LUCK</em>
Answer:
True.
But it only changes in physical change.
How?
Explanation:
The chemical reaction produces a new substance with new and different physical and chemical properties. Matter is never destroyed or created in chemical reactions. The particles of one substance are rearranged to form a new substance.
In a physical change, a substance's physical properties may change.
A chemical change is a permanent change. A Physical change affects only physical properties i.e. shape, size, etc. ... Some examples of physical change are freezing of water, melting of wax, boiling of water, etc. A few examples of chemical change are digestion of food, burning of coal, rusting, etc.
Hope this helps!
Molarity is expressed as:
Molarity = moles / liter
Given that the cell is rod-shaped, its volume is calculated using the formula for a cylinder's volume:
V = πr²L
V = π * (0.6)² * 4.9
V = 5.54 μm³
1 Liter = 10³ mm³
1 mm = 10³ μm
1 mm³ = 10⁹ μm³
1 liter = 10¹² μm³
So the volume in liters is:
5.54 x 10⁻¹² L
Moles = molarity * liters
Moles = 0.0029 * 5.54 x 10⁻¹²
Moles = 1.61 x 10⁻¹⁴
To get the number of molecules, we multiply the moles by Avagadro's number
Number of molecules = 1.61 x 10⁻¹⁴ * 6.02 x 10²³
There are 9.69 x 10⁹ molecules in the cell
Answer:
Animals gain energy from the food they eat. Some animals eat plants while others eat other animals. This is passing of energy from the sun to plants to animal to other animals is called a food chain