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3 years ago

12

SOLVE ANY BUT PUT THE NUMBER WITH IT

1 answer:

zubka84 [21]3 years ago

8 0

1.
k = 1
J = 7(1) + 5
J = 12

k = 1 + 2 = 3
J = 7(3) + 5
J = 26

26 - 12 = 14
J increases by 14.

2.
1/6 = 0.16 false (1/6 = 1.67)
0.08 = 4/5 false (0.08 = 8/100 = 2/25)
0.25 = 1/4 true (0.25 = 25/100 = 1/4)
<span>1/3 = 0.3 true (if rounded)</span>
<span>

3.
12 candles in 3 hours
12 </span>÷ 3 = 4
4 candles in 1 hour
4 × 8 = 32
32 candles in 8 hours

4.
$3.45 for 64 ounces
3.45 ÷ 64 = 0.05
$0.05 or 5 cents per ounce

5.
75 is what percent of 250?
75 ÷ 250 = 0.3
0.3 × 100 = 30
30%

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What is the factorization of the following trinomial? 15x2 - 44x - 36

BartSMP [9]

$15x^2-44x-36$

$=(15x^2+10x)+(-54x-36)$

factor out 5x from $15x^2+10x = 5x(3x+2)$

Factor out -18 from $-54x-36 = -18(3x+2)$

$=5x(3x+2)-18(3x+2)$

Factor out common term $(3x+2)$

$= (3x+2)(5x-18)$

hope this helps!

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2 years ago

Lucy’s order at the restaurant came out to $44.20. She decided to leave a 15% tip for the waitress. What is the overall total am

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$50.83

Step-by-step explanation:

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2 years ago

Solve 6(x + 1) > 2x - 1<br><br> x > -1/2<br> x > -7/4<br> x > 0

Bond [772]

Answer:

x > - $\frac{7}{4}$

Step-by-step explanation:

Given

6(x + 1) > 2x - 1 ← distribute parenthesis on left side

6x + 6 > 2x - 1 ( subtract 2x from both sides )

4x + 6 > - 1 ( subtract 6 from both sides )

4x > - 7 ( divide both sides by 4 )

x > - $\frac{7}{4}$

6 0

2 years ago

Read 2 more answers

I'm genuinely lost in any problems like this and my teachers are no help, I need help doing exponents in general, everything to

Stolb23 [73]

Answer:

See below.

Step-by-step explanation:

4)

So we have the expression:

$(-6n^{-3})^2$

We can use the power of a product property, where:

$(ab)^n=a^n\cdot b^n$

So:

$=(-6)^2\cdot(n^{-3})^2$

For the left, -6 squared is the same as -6 times -6. This equals positive 36.

For the right, we can use the power of a power property. The property says that:

$(a^n)^k=a^{nk}$

So:

$(n^{-3})^2=n^{(-3)(2)}\\=n^{-6}$

So, all together, we have:

$=(-6)^2\cdot(n^{-3})^2\\=36n^{-6}$

6)

We have the expression:

$-\frac{3x^0}{x^4}$

First, note that anything to the zeroth power (except for 0) is 1, thus, x^0 is also 1. Simplify:

$=-\frac{3}{x^4}$

And that's the simplest we can do :)

Notes for 6)

We <em>can</em> put the x^4 to the numerator. Recall that when you put an exponent to opposite side, you put a negative. In other words:

$x^n=\frac{1}{x^{-n}}$

And vice versa:

$\frac{1}{x^{-n}}=x^n$

So, we can write the above as:

$=-\frac{3}{x^4}\\=-\frac{3}{x^{-(-4)}}\\=-3x^{-4}$

However, traditionally, we want only positive exponents, so this wouldn't be correct.

4 0

3 years ago

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The coordinates of the four vertices of the rectangle are (1,-1), (4,-1), (4,1), and (1,1). The perimeter of the rectangle is ho

vlada-n [284]

Answer:

10

Step-by-step explanation:

4-1=3 (length of base)

-1-1=-2 (absolute value of height is 2)

3+2+2+3=10

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2 years ago