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3 years ago

13

Video games are on sale for $4 and $8 including tax. Roberto has $32 to spend if he purchases one video prices for $8 how many $

4 videos can Roberto purchase

1 answer:

Fudgin [204]3 years ago

5 0

Answer:

6

Step-by-step explanation:

take 32 and subtract 8 which then u get 24 and divide that by 4 which is 6

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HELP!!!! PLEASE I NEED HELP!!!!

NNADVOKAT [17]

for the first one it is the second option because of one property of logarithms:

log(a)-log(b)=log $\frac{a}{b}$

for the second one using the same property we can say that we third option is correct and not the second one but we use one more property of the logarithm

loga(b)^x=xloga(b) the power of the logarithm becomes a fator and $\sqrt[3]{x}$ is equal to $x^{\frac{1}{3}}$

8 0

3 years ago

Ski rentals are $100 plus $18 per hour, as shown in the table above.

lisabon 2012 [21]

Answer:

1. f(x)=18X +100

2:108

3. 7.5

Step-by-step explanation:

3 0

2 years ago

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there are 6 glass bottles and eight plastic bottles on a rack. I f one is chosen at random, what is the probability of picking a

netineya [11]

Answer:

6:8

Step-by-step explanation:

6 is the ratio of glass bottles and 8 is the plastic or you can put 3:4 because you divide the number b 2

3 0

2 years ago

Element X decays radioactively with a half life of 12 minutes. If there are 200 grams of Element X, how long, to the nearest ten

Semenov [28]

Answer:

It would take 24 minutes for the element to decay to 50 grams

Step-by-step explanation:

The equation for the amount of the element present, after t minutes, is:

$Q(t) = Q(0)e^{-rt}$

In which Q(X) decays radioactively with a half life of 12 minutes.(0) is the initial amount and r is the rate it decreases.

Half life of 12 minutes

This means that $Q(12) = 0.5Q(0)$

So

$Q(t) = Q(0)e^{-rt}$

$0.5Q(0) = Q(0)e^{-12r}$

$e^{-12r} = 0.5$

$\ln{e^{-12r}} = \ln{0.5}$

$-12r = \ln{0.5}$

$12r = -\ln{0.5}$

$r = -\frac{\ln{0.5}}{12}$

$r = 0.05776$

If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?

This is t when Q(t) = 50. Q(0) = 200.

$Q(t) = Q(0)e^{-rt}$

$50 = 200e^{-0.05776t}$

$e^{-0.05776t} = 0.25$

$\ln{e^{-0.05776t}} = \ln{0.25}$

$-0.05776t = \ln{0.25}$

$0.05776t = -\ln{0.25}$

$t = -\frac{\ln{0.25}}{0.05776}$

$t = 24$

It would take 24 minutes for the element to decay to 50 grams

6 0

3 years ago

Anyone know this please

Komok [63]

I would think it would be P

Once reflected over x, the point would be over Point J, once over Y it would be over point P, answer is B

I hope this helps

3 0

2 years ago

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