Answer:
The correct order would be
- Glucose
- ATP→ADP
- H₂O
- Pyruvate
- CO₂
Explanation:
Following reactions occur in Glycolysis and Kreb's Cycle
- Phosphorylation of Glucose- In the first step of glycolysis, Glucose is converted into Glucose-6-Phosphate using 1 ATP molecule by Hexokinase enzyme. One phosphate group from ATP is attached to glucose by the enzyme, thus forming ADP.
- Dehydration- In the ninth step of Glycolysis, each of two molecules of 2-Phosphoglycerate are converted to Phosphoenol Pyruvate, by Enolase enzyme, releasing two H₂O molecules.
- Formation of Pyruvate- In the last or tenth step of Glycolysis, each of two molecules of Phosphoenol Pyruvate are converted to Pyrutave using an ATP by the enzyme Pyruvate Kinase.
- Oxidation Of Pyruvate to Acetyl-CoA- Before the Kreb's Cycle starts, the Pyruvate molecule obtained from the Glycolysis undergoes oxidative decarboxylation producing Acetyl-CoA and release of CO₂ and NADH.
Answer:
It's good to give healthy food to your body.
Explanation:
Hope this helps
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Melting ice caps and glaciers
Answer:
The correct answer is A the compound is a competitive inhibitor
Explanation:
Competitive inhibitor competes with the substrate to bind to the active site of the target enzyme and after binding to the active site the inhibitor slow down or stop the reaction catalyzed by that enzyme.
Competitive inhibitor basically effects the Km value of the enzyme thus decreasing the activity of the later.
Increasing the substrate concentration displace the inhibitor from the enzyme"s active site thus reducing the inhibitory effects of the later thus increasing the activity of the enzyme.
As the flower takes water that it needs to survive, the dye in it has no more density so it goes up with the water dying everything in its path blue.
