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Ann [662]
3 years ago
8

After writing and balancing the equation, what's the next step in using bond energies to calculate the enthalpy of a reaction? Q

uestion 11 options: A) Subtract the bond energies of the products from the reactants. B) Sum the bond energies of the products. C) Write the structures of the products and reactants. D) Write down the bond energies for the products and reactants.
Chemistry
1 answer:
Bas_tet [7]3 years ago
8 0

Answer:

D. write down the bond energies for the reactants and product.

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What are the coefficients that will balance this skeleton equation? AlCl3 + NaOH → Al(OH)3 + NaCl
almond37 [142]

Answer:

The coefficients are 1, 3, 1, 3

Explanation:

The equation;

AlCl3 + NaOH → Al(OH)3 + NaCl

can be balanced by using the coefficients  1, 3, 1, 3, such that the balanced equation will be;

AlCl3 + 3NaOH → Al(OH)3 + 3NaCl

Chemical equations needs to be balanced so as to follow the law of conservation of mass. This occurs when the number of the different atoms of elements in the reactants side is equal to that of the products side.

3 0
3 years ago
the volume of a gas is 550 ml at 960 mm hg and 200.0°C. What volume would the pressure of the gas be 830 mm Hg if the temperatur
gavmur [86]

Answer:

V₂ = 568.9 mL

Explanation:

Given data:

Volume of gas = 550 mL

Pressure of a gas = 960 mmHg

Temperature = 200.0°C ( 200+273 = 473 K)

Final volume = ?

Final pressure = 830 mmHg

Final temperature = 150°C (150+273 = 423 K)

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 960 mmHg × 550 mL × 423 K / 473 K ×830 mmHg

V₂ = 223344000 mL / 392590

V₂ = 568.9 mL

8 0
3 years ago
A trait developed through learning is a(n)___________
matrenka [14]
An acquired trait is a trait developed through learning. (:
5 0
3 years ago
Read 2 more answers
An unknown compound contains only C, H, and O. Combustion of 8.50 g of this compound produced 20.0 g CO2 and 5.46 g H2O. What is
Galina-37 [17]

Answer:

The answer to your question is: C₃H₄O

Explanation:

Data

CxHyOz = 8.5 g

CO2 = 20 g

H2O = 5.46 g

Reaction

             CxHyOz + O2     ⇒    CO2   +    H2O

CO2

    MW = 44g

                       44g CO2 ----------------- 12g of C

                        20g CO2 ----------------   x

                       x = (20 x 12) / 44

                       x = 5.45 g of C

                     # of moles = n = 5.45 / 12 = 0.454 mol of C

H2O

     MW = 18 g

                       18 g H2O ------------------- 2g of H

                       5.46 g    --------------------   x

                       x = (5.46 x 2) / 18 = 0.61 g of H

                       n = 0.61 / 1 = 0.61 moles of H2

Mass of O2

              mass CxHyOz = mass CO2 + mass H2 + mass O2

              mass O2 = 8.5 - 5.45 - 0.61

              mass O2 = 2.44g

              n = 2.44 / 16 = 0.153 mol of O2

Now, divide by the lowest number of moles

0.454 mol of C/ 0.153 = 2.97 ≈ 3

0.61 moles of H2/ 0.153 = 3.99 ≈ 4

0.153 mol of O2/ 0.153 =  1

Then, the empirical formula is: C₃H₄O

7 0
3 years ago
Which describes what happens when a wave transfers energy? A. Waves carry energy toward the energy source through space or throu
Mandarinka [93]

A. Waves carry energy toward the energy source through space or through matter, and the matter moves with the energy
7 0
3 years ago
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