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Grace [21]
3 years ago
8

One meter is equal to 100.0 cm (1 m = 100 cm). Use your data from Trial 4 to calculate the average speed of the rolling ball in

m/s (meters per second).
Physics
1 answer:
lions [1.4K]3 years ago
3 0

Answer:

v=1.35m/s

Explanation:

Hello,

In this case, since the given information shows that the traveled distance by the rolling ball was 400 cm that in meters is:

400 cm*\frac{1m}{100cm}=4m

Thus, since the average speed is computed by using the distance and time (which was 2.97 s for this experiment):

v=\frac{d}{t}

Thus, we obtain in m/s:

v=\frac{4m}{2.97s}\\ \\v=1.35m/s

Best regards.

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a string with fixed ends is made to go into standing wave patterns. at a given tension, the lowest frequency for which a certain
lakkis [162]

Answer:

700 hz

Explanation:

3 0
3 years ago
A 70 kg football player running at 3m/s north tackles an 80kg player running at 1.5 m/s south. what is the magnitude and directi
dimulka [17.4K]
It could never actually happen like this, but the question is
looking for you to 'conserve' the momentum.

Momentum of a moving object is (mass) x (velocity).
Like velocity, momentum has a direction.
Momentum is one of those things that's 'conserved'. 
That means that momentum can't appear out of nowhere, and
it doesn't disappear.  The total after the collision is the same as
the total was before the collision.  

Momentum of the skinny player:

                     (70 kg) x (3 m/s north) = 210 kg-m/s north.

Momentum of the heavy player:

                     (80 kg) x (1.5 m/s south)  =  120 kg-m/s south .

Total momentum before the collision is

                     (210 kg-m/s north) + (120 kg-m/s south)

                 =        90 kg-m/s north  .

It has to be the same after the collision.

                       (mass) x (velocity)  =  90 kg-m/s north.

The  mass after the collision is 150 kg, because they get
tangled up and stuck together, and they move together.

                                (150 kg) x (velocity)  =  90 kg-m/s north .

Divide each side
by  150 kg :                   velocity  =  (90 kg-m/s north) / (150 kg)

                                                =  (90/150)  (kg-m/s / kg  north)

                                                 =        0.6 m/s  north  .
3 0
3 years ago
The jogger ran 3km east.
erma4kov [3.2K]

Answer: d

Explanation:

7 0
4 years ago
Which equation could represent “the area of a square as a function of a slide”
AfilCa [17]

A=f(a)=a^2

8 0
3 years ago
Read 2 more answers
What formula gives the strength of an electric field, E, at a distance from a known source charge?
Deffense [45]
<h2>Hello!</h2>

The answer is: Coulomb's law equation.

<h2>Why?</h2>

The Coulomb's law states that the strength of an electric field (between two charges) can be calculated by multiplying their charges and dividing it into the square of the distance between their centers.

E=\frac{k*q*Q}{d^{2} }

Where:

E = Electric Field Strenght

k=9.0*10^{9}  \frac{N.m^{2} }{C^{2} }

q=TestCharge\\Q=SourceCharge\\

d = separation between charges (m)

Have a nice day!

5 0
4 years ago
Read 2 more answers
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