This energy transformation diagram represents the
2 answers:
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Given that,
Mass of trackler, m₁ = 100 kg
Speed of trackler, u₁ = 2.6 m/s
Mass of halfback, m₂ = 92 kg
Speed of halfback, u₂ = -5 m/s (direction is opposite)
To find,
Mutual speed immediately after the collision.
Solution,
The momentum of the system remains conserved in this case. Let v is the mutual speed after the collision. Using conservation of momentum as :
So, the mutual speed immediately after the collision is 1.04 m/s but in opposite direction.
Answer:
The mass of the object is 24.5 kg and weight of the object on Mars is 91.14 N.
Explanation:
Weight of the object on the surface of Earth, W = 245 N
On the surface of Earth, acceleration due to gravity, g = 10 m/s²
Weight of an object is given by :
W = mg
m is mass
So, the mass of the object is 24.5 kg
Acceleration due to gravity on Mars, g' = 3.72 m/s²
Weight of the object on Mars,
W' =mg'
W' = 24.5 kg × 3.72 m/s²
= 91.14 N
So, the weight of the object on Mars is 91.14 N.