Question

A force of 1.5 × 102 n is exerted on a charge of 1.4 × 10–7 c that is traveling at an angle of 75° to a magnetic field. if the charge is moving at 1.3 × 106 m/s, what is the magnetic field strength?

Answer 1

The magnetic field strength = 8.5 x 10² T.

Solution :

the magnetic force Fm is given by

Fm= q V B sinθ

q= charge=1.4 x 10⁻⁷ C

v= velocity= 1.3 x 10⁶ m/s

B= magnetic field strength

Fm= magnetic force= 1.5 x 10² N

θ=75°

so 1.5 x 10²=(1.4 x 10⁻⁷) (1.3 x 10⁶ ) (B) sin75

B=8.5 x 10² T

Magnetic field strength: The definition of H is H = B/μ − M, where B is the magnetic flux density, a measure of the actual magnetic field within a material considered as a concentration of magnetic field lines, or flux, per unit cross-sectional area; μ is the magnetic permeability; and M is the magnetization.

To learn more about magnetic field strength refer : brainly.com/question/18651668

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