Answer:
The answer to your question is Abundance N-14 = 99.63%
Abundance N-15 = 0.37%
Explanation:
Data
Average atomic mass = 14.0067 amu
N-14 = 14.003074002
N-15 = 15.00010897
Abundance N-14 = ? x
Abundance N-15 = ? 1 - x
Formula
Average atomic mass = (mass of N-14)x + (mass of N-15)(1 - x)
Substitution
14.0067 = 14.003074002x + 15.00010897(1 - x)
Solve for x
14.0067 = 14.003074002x + 15.00010897 - 15.00010897x
14.0067 - 15.00010897 = 14.003074002x - 15.00010897x
-0.9934 = -0.99703x
x = -0.9934 / -0.99703
x = 0.9963
Conclusion
Abundance N-14 = 0.9963 x 100 = 99.63 %
Abundance N-15 = 1 - 0.9963 = 0.0037 x 100 = 0.37 %
b the absence of a nucleus
<h3><u>Answer;</u></h3>
Higher velocity of particles
<h3><u>Explanation;</u></h3>
The diffusion rate is determined by a variety of factors which includes;
- Temperature such that the higher the temperature, the more kinetic energy the particles will have, so they will move and mix more quickly and the diffusion rate will be high.
- Concentration gradient such that the greater the difference in concentration, the quicker the rate of diffusion.
- Higher velocity of particles increases the diffusion rate as this means more kinetic energy by the particles and hence the particles will mix and move faster, thus higher diffusion rate.
Your answer would be D. As the circulatory system pumps oxygen rich blood through the body, and the respiratory system helps you to breath. Hope this helps!
3.8mL of 0.42 phosphoric acid is required.
Reaction
2H3PO4 + 3CaCL3 → Ca3(PO)4 + 6HCl
moles CaCl2 =0.16 mol/L x0.010 L = 0.0016 mol
moles of H3Po4
= 0.0016mol of CaCl2 x 2 mole of H3PO4/3mole of CaCl2
= 0.00106 mol
V of H3PO4 = 0.0016/0.42 = 0.0038L = 3.8mL
V of H3PO4=3.8mL
To know more about calculation in milliliters refer to:-
brainly.com/question/23276655
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